Javascript map 不是试图读取数据的函数
Javascript map is not a function what trying to read data
我正在尝试填充图表,因此我将数据放入 2 个列表中以执行此操作。
这是数据:
var data = [{
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": " Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
}];
我运行此代码是为了填充列表:
var chList = [];
var boatList = [];
var boatCount = [];
for (var i = 0; i < data.length; i++) {
var obj = data[i];
var cl = obj.name + " [" + obj.id + "]";
if (obj.boats != null) {
chList.push(cl);
}
if(obj.boats) {
var nme = obj.boats.map( function(item){
return item.name;
});
boatList = boatList.concat(nme);
boatCount.push(nme.length);
}
}
console.log(boatList);
console.log(boatCount);
我的问题是我不断收到:
TypeError: obj.boats.map 不是函数
我该如何解决这个问题?
注:数据其实是这样的:
{
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": " Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
};
但我向其中添加了 [ 和 ] 以便使用 data.length 并且列表也是空的...然后我是否保留这些数据?
boats
是对象,不是数组。映射用于数组。
您可以使用 for ( in )
循环或 Object.keys()
获取键数组并使用它。
问题是 obj.boats
是一个对象,而不是数组,因此没有 map
方法。
试试这个:
Object.keys(obj.boats).map(function(k) { return obj.boats[k].name; });
见MDN
其他两个答案是正确的,不过我会更改数据:
"boats": [
{
"id": "637",
"name": " Subcat 1",
"translations": null
},
{
"id": "638",
"name": "Subcat 2",
"translations": null
}
],
使用 id 作为键然后给包含对象一个 "id" 属性 有点毫无意义。当您将数据更改为此结构时,您的代码将正常工作。
除了已经正确指向 obj.boats
是 Object
而不是 Array
的所有其他答案之外,我想提供一个解决方案来展示 [= 的优雅之美15=] ...
var boatChartData = [{
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": "Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
}, {
"id": "623",
"name": "other name",
"boats": {
"639": {
"id": "639",
"name": "Supercat",
"translations": null
},
"640": {
"id": "640",
"name": "Supercat II",
"translations": null
},
"641": {
"id": "641",
"name": "Supercat III",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6295c"
}];
function collectBoatChartData(collector, chartItem/*, idx, list*/) {
var
boatNameList,
boatMap = chartItem.boats;
if (boatMap != null) {
collector.chartItemTitleList.push([
chartItem.name,
" [",
chartItem.id,
"]"
].join(""));
boatNameList = Object.keys(boatMap).map(collector.getBoatNameByKey, boatMap);
collector.boatNameList = collector.boatNameList.concat(boatNameList);
//collector.chartItemBoatNameList.push(boatNameList);
collector.chartItemBoatCountList.push(boatNameList.length);
}
return collector;
}
var processedBoatChartData = boatChartData.reduce(collectBoatChartData, {
getBoatNameByKey: function (key) {
return this[key].name;
},
boatNameList: [],
chartItemTitleList: [],
//chartItemBoatNameList: [],
chartItemBoatCountList: []
});
console.log("processedBoatChartData.boatNameList : ", processedBoatChartData.boatNameList);
console.log("processedBoatChartData.chartItemTitleList : ", processedBoatChartData.chartItemTitleList);
//console.log("processedBoatChartData.chartItemBoatNameList : ", processedBoatChartData.chartItemBoatNameList);
console.log("processedBoatChartData.chartItemBoatCountList : ", processedBoatChartData.chartItemBoatCountList);
备注
考虑到OP的附加评论,提到提供的axample的真实数据结构,我上面提供的解决方案只是更改为...
var boatChartData = {
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": "Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
};
var processedBoatChartData = [boatChartData].reduce(collectBoatChartData, {
getBoatNameByKey: function (key) {
return this[key].name;
},
boatNameList: [],
chartItemTitleList: [],
//chartItemBoatNameList: [],
chartItemBoatCountList: []
});
..,证明通用解决方案可以很容易 recycled/adapted,例如数据结构确实发生了变化。
我正在尝试填充图表,因此我将数据放入 2 个列表中以执行此操作。
这是数据:
var data = [{
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": " Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
}];
我运行此代码是为了填充列表:
var chList = [];
var boatList = [];
var boatCount = [];
for (var i = 0; i < data.length; i++) {
var obj = data[i];
var cl = obj.name + " [" + obj.id + "]";
if (obj.boats != null) {
chList.push(cl);
}
if(obj.boats) {
var nme = obj.boats.map( function(item){
return item.name;
});
boatList = boatList.concat(nme);
boatCount.push(nme.length);
}
}
console.log(boatList);
console.log(boatCount);
我的问题是我不断收到:
TypeError: obj.boats.map 不是函数
我该如何解决这个问题?
注:数据其实是这样的:
{
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": " Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
};
但我向其中添加了 [ 和 ] 以便使用 data.length 并且列表也是空的...然后我是否保留这些数据?
boats
是对象,不是数组。映射用于数组。
您可以使用 for ( in )
循环或 Object.keys()
获取键数组并使用它。
问题是 obj.boats
是一个对象,而不是数组,因此没有 map
方法。
试试这个:
Object.keys(obj.boats).map(function(k) { return obj.boats[k].name; });
见MDN
其他两个答案是正确的,不过我会更改数据:
"boats": [
{
"id": "637",
"name": " Subcat 1",
"translations": null
},
{
"id": "638",
"name": "Subcat 2",
"translations": null
}
],
使用 id 作为键然后给包含对象一个 "id" 属性 有点毫无意义。当您将数据更改为此结构时,您的代码将正常工作。
除了已经正确指向 obj.boats
是 Object
而不是 Array
的所有其他答案之外,我想提供一个解决方案来展示 [= 的优雅之美15=] ...
var boatChartData = [{
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": "Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
}, {
"id": "623",
"name": "other name",
"boats": {
"639": {
"id": "639",
"name": "Supercat",
"translations": null
},
"640": {
"id": "640",
"name": "Supercat II",
"translations": null
},
"641": {
"id": "641",
"name": "Supercat III",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6295c"
}];
function collectBoatChartData(collector, chartItem/*, idx, list*/) {
var
boatNameList,
boatMap = chartItem.boats;
if (boatMap != null) {
collector.chartItemTitleList.push([
chartItem.name,
" [",
chartItem.id,
"]"
].join(""));
boatNameList = Object.keys(boatMap).map(collector.getBoatNameByKey, boatMap);
collector.boatNameList = collector.boatNameList.concat(boatNameList);
//collector.chartItemBoatNameList.push(boatNameList);
collector.chartItemBoatCountList.push(boatNameList.length);
}
return collector;
}
var processedBoatChartData = boatChartData.reduce(collectBoatChartData, {
getBoatNameByKey: function (key) {
return this[key].name;
},
boatNameList: [],
chartItemTitleList: [],
//chartItemBoatNameList: [],
chartItemBoatCountList: []
});
console.log("processedBoatChartData.boatNameList : ", processedBoatChartData.boatNameList);
console.log("processedBoatChartData.chartItemTitleList : ", processedBoatChartData.chartItemTitleList);
//console.log("processedBoatChartData.chartItemBoatNameList : ", processedBoatChartData.chartItemBoatNameList);
console.log("processedBoatChartData.chartItemBoatCountList : ", processedBoatChartData.chartItemBoatCountList);
备注
考虑到OP的附加评论,提到提供的axample的真实数据结构,我上面提供的解决方案只是更改为...
var boatChartData = {
"id": "622",
"name": "some name",
"boats": {
"637": {
"id": "637",
"name": "Subcat 1",
"translations": null
},
"638": {
"id": "638",
"name": "Subcat 2",
"translations": null
}
},
"image": "73e043a7fae04b55855bede22da6286b"
};
var processedBoatChartData = [boatChartData].reduce(collectBoatChartData, {
getBoatNameByKey: function (key) {
return this[key].name;
},
boatNameList: [],
chartItemTitleList: [],
//chartItemBoatNameList: [],
chartItemBoatCountList: []
});
..,证明通用解决方案可以很容易 recycled/adapted,例如数据结构确实发生了变化。