Python 的 matplotlib 中如何获取当前图形编号？

Question

我正在研究一个示例脚本，该脚本展示了如何在数字之间来回切换。我在这里找到了示例：http://matplotlib.org/examples/pylab_examples/multiple_figs_demo.html 当我尝试打印数字时，我得到 "Figure(640x480)" 而不是我期望的数字 1。你是怎么得到这个号码的？

# Working with multiple figure windows and subplots
import matplotlib.pyplot as plt
import numpy as np

t = np.arange(0.0, 2.0, 0.01)
s1 = np.sin(2*np.pi*t)
s2 = np.sin(4*np.pi*t)

plt.figure(1)
plt.subplot(211)
plt.plot(t, s1)
plt.subplot(212)
plt.plot(t, 2*s1)

plt.figure(2)
plt.plot(t, s2)

# now switch back to figure 1 and make some changes
plt.figure(1)
plt.subplot(211)
plt.plot(t, s2, 's')
ax = plt.gca()
ax.set_xticklabels([])

# Return a list of existing figure numbers.
print "Figure numbers are = " + str(plt.get_fignums())
print "current figure = " + str(plt.gcf())
print "current axes   = " + str(plt.gca())

plt.show()

这是输出：

Figure numbers are = [1, 2]
current figure = Figure(640x480)
current axes   = Axes(0.125,0.53;0.775x0.35)

Answer 1

Figure对象有一个number属性，所以可以通过

获取号码

>>> plt.gcf().number

Python 的 matplotlib 中如何获取当前图形编号？

How do you get the current figure number in Python's matplotlib?

python

matplotlib

figure