Swift 3 将变量传递给 PopupViewController

Question

我正在使用 accessoryButtonTappedForRowWith:

来展示我的 viewController

let storyboard : UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
        let popoverContent = storyboard.instantiateViewController(withIdentifier: "Test")

        popoverContent.modalPresentationStyle = .popover

        if let popover = popoverContent.popoverPresentationController {
            let viewForSource = self.createCharacterView as UIView
            popover.sourceView = viewForSource

            // the position of the popover where it's showed
            popover.sourceRect = viewForSource.bounds

            // the size you want to display
            popoverContent.preferredContentSize = CGSize(width: 200,height: 200)
            popover.delegate = self
        }

        self.present(popoverContent, animated: true, completion: nil)

弹出窗口工作正常，只是我显示的 viewController 需要 tableViewCell 的标签。我能够获取变量，但我不确定如何将变量传递给弹出窗口，因为未调用 segue 我认为我无法使用 prepare(for segue: UIStoryboardSegue, sender: Any?).

Answer 1

太简单了：

popoverContent.variableName = passingVariable

Answer 2

您可能需要将 popOvercontent 转换为特定的 viewController

(popoverContent as? MyViewController).myVar = value

Swift 3 将变量传递给 PopupViewController

Swift 3 Pass variable to PopupViewController

popover

ios

swift3