从 mysql 中的一手牌中找出两对

Question

嗨，我需要帮助来弄清楚如何从一手牌中找到两对。我相信我需要计算不同卡片的数量，然后根据以下逻辑告诉我它是否是两对，即两对是一手扑克牌，包含两张相同等级的牌，两张另一等级的牌和一张牌第三等级；我只是不确定该怎么做。

感谢任何帮助。

这是我的扑克牌table

+----------+------+------+------+-----------+-----------+
| cardName | face | type | suit | faceValue | gameValue |
+----------+------+------+------+-----------+-----------+
| AC       | no   | A    | C    |         1 |        14 |
| 2C       | no   | 2    | C    |         2 |         2 |
| 3C       | no   | 3    | C    |         3 |         3 |
| 4C       | no   | 4    | C    |         4 |         4 |
| 5C       | no   | 5    | C    |         5 |         5 |
+----------+------+------+------+-----------+-----------+

和扑克牌手

+----------+--------+----+-----+----+----+----+----------+
| playerId | gameId | C1 | C2  | C3 | C4 | C5 | handType |
+----------+--------+----+-----+----+----+----+----------+
|    12789 | 17MET  | QH | QS  | 3D | 3C | 3H |          |
|    12789 | 82SAT  | 7C | 4S  | 4D | 4C | 3H |          |
|    56347 | 03DEC  | 6S | 3S  | 3H | 3C | 3D |          |
|    56347 | 23WSA  | KH | 10H | 7H | 3H | AH |          |
|    56347 | 30DEC  | AC | KH  | KD | 3D | 3S |          |
+----------+--------+----+-----+----+----+----+----------+

我需要获取最后一行

+----------+--------+----+-----+----+----+----+----------+
| playerId | gameId | C1 | C2  | C3 | C4 | C5 | handType |
+----------+--------+----+-----+----+----+----+----------+
|    56347 | 30DEC  | AC | KH  | KD | 3D | 3S |          |
+----------+--------+----+-----+----+----+----+----------+

Answer 1

正如我在评论中所说，用适合此类事情的语言来完成要好得多。 SQL 不是完成这项工作的正确工具。仅作为学术练习，这是您需要的声明：

select *
   from pokerCard
  where (left(c1,1) = left(c2,1) and left(c3,1) = left(c4,1))
     or (left(c1,1) = left(c2,1) and left(c3,1) = left(c5,1))
     or (left(c1,1) = left(c2,1) and left(c4,1) = left(c5,1))
     or (left(c1,1) = left(c3,1) and left(c2,1) = left(c4,1))
     or (left(c1,1) = left(c3,1) and left(c2,1) = left(c5,1))
     or (left(c1,1) = left(c3,1) and left(c4,1) = left(c5,1))
     or (left(c1,1) = left(c4,1) and left(c2,1) = left(c3,1))
     or (left(c1,1) = left(c4,1) and left(c2,1) = left(c5,1))
     or (left(c1,1) = left(c4,1) and left(c3,1) = left(c5,1))
     or (left(c1,1) = left(c5,1) and left(c2,1) = left(c3,1))
     or (left(c1,1) = left(c5,1) and left(c2,1) = left(c4,1))
     or (left(c1,1) = left(c5,1) and left(c3,1) = left(c4,1))
     or (left(c2,1) = left(c3,1) and left(c1,1) = left(c4,1))
     or (left(c2,1) = left(c3,1) and left(c1,1) = left(c5,1))
     or (left(c2,1) = left(c3,1) and left(c4,1) = left(c5,1))
     or (left(c2,1) = left(c4,1) and left(c3,1) = left(c5,1))
     or (left(c2,1) = left(c5,1) and left(c3,1) = left(c4,1))

Answer 2

我会通过 UNION 将每张牌作为预聚合来处理，以获得普通牌，而不管花色如何。然后申请一个组...

select  PlayerID, GameID, left( c1,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c2,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c3,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c4,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c5,1 ) as OneCard
   from PlayerHand

这会给你一个类似下面的东西 person/game

playerid  gameid  onecard
12789     17MET   Q
12789     17MET   Q
12789     17MET   3 
12789     17MET   3
12789     17MET   3

现在，您可以轻松查看卡片并进行简单聚合

select
      preQuery.playerid,
      preQuery.gameid,
      preQuery.onecard,
      count(*) as CntThisCard
   from
      ( the entire union query above ) preQuery
   group by
      preQuery.playerid,
      preQuery.gameid,
      preQuery.onecard
   having
      count(*) > 1

根据您的数据，这将 return 以下行...

playerid  gameid  onecard  cntThisCard
12789     17MET   Q        2
12789     17MET   3        3  This is a full-house
12789     82SAT   4        3  Three-of-a-kind
56347     03DEC   3        4  Four-of-a-kind
56347     23WSA   (not returned in data set)
56347     30DEC   K        2
56347     30DEC   3        2  Two-pair

那么现在，如何提取任何内容 "hand" 这也会卷起来...

select
      QryLvl2.PlayerID,
      QryLvl2.GameID
   from
      ( the entire query above returning per-card count ) QryLvl2
   where
      QryLvl2.CntThisCard = 2
   group by
      QryLvl2.PlayerID,
      QryLvl2.GameID
   having
      count(*) = 2

在这种情况下，由于您要明确地寻找两对，所以我有 where 子句明确地只寻找手中有 2 的牌。计数 (*) = 2 的组表示两张不同的牌，它们会给你最后一手牌。

但是从第二张可以看出，你也可以立即识别出更好的4张、葫芦、3张、2对和单高牌。

然后您可以将牌 table 简化为 number/face 以确定一对 Jacks/3 是比 10 和 9 更高的牌，因为您不在乎关于牌的花色，只是与其他手牌相比的面值。

从 mysql 中的一手牌中找出两对

find a two pair from a poker hand in mysql

mysql

mysql-5.7