蛮力脚本

Question

我正在创建一个简单的暴力破解脚本，但我似乎不太明白。我正在使用来自 this question 的已接受答案，但我无法让 'attempt' 等于用户密码。下面是我使用的代码（来自链接的问题），并做了一些改动。

from string import printable
from itertools import product

user_password = 'hi' # just a test password
for length in range(1, 10): # it isn't reasonable to try a password more than this length
    password_to_attempt = product(printable, repeat=length)
    for attempt in password_to_attempt:
        if attempt == user_password:
            print("Your password is: " + attempt)

我的代码一直运行到到达笛卡尔坐标的末尾，并且从不打印最终答案。不确定发生了什么。

如有任何帮助，我们将不胜感激！

Answer 1

itertools.product() 为您提供元组而非字符串的集合。所以，你最终可能会得到结果 ('h', 'i')，但这和 'hi'.

是不一样的

您需要将字母组合成一个字符串进行比较。另外，您应该在找到密码后停止该程序。

from string import printable
from itertools import product

user_password = 'hi' # just a test password
found = False

for length in range(1, 10): # it isn't reasonable to try a password more than this length
    password_to_attempt = product(printable, repeat=length)

    for attempt in password_to_attempt:
        attempt = ''.join(attempt) # <- Join letters together

        if attempt == user_password:
            print("Your password is: " + attempt)
            found = True
            break

    if found:
        break

Try it online!

蛮力脚本

Brute Force Script

brute-force

python-3.x