ElasticSearch : TypeError: expected string or buffer?

Question

我写了一个简单的 python 脚本来把 JSON 文件放到 Elasticsearch.I 想根据我从 JSON 文件中提取的 id 字段存储它. 但是当我尝试插入弹性 search.It 时会引发错误 TypeError: expected string or buffer

这是我正在处理的代码...

#! /usr/bin/python

import requests
from elasticsearch import Elasticsearch
import json
es = Elasticsearch([{'host':'localhost','port':9200}])
r = requests.get('http://127.0.0.1:9200')
i = 1
if r.status_code == 200:

        with open('d1.json') as json_data:
                d = json.load(json_data)

                for i in d['tc'][0]['i]['f']['h']:
                        if i['name'] == 'm':
                                m = i['value']
                                dope=str(m)
                                print dope
                                print type(dope)
                                #print type(md5)
                                es.index(index='lab', doc_type='report',id=dope,body=json.loads(json_data))

错误日志：

44d88612fea8a8f36de82e1278abb02f
<type 'str'>
Traceback (most recent call last):
  File "elastic_insert.py", line 22, in <module>
    es.index(index='labs', doc_type='report',id=dope,body=json.loads(json_data))
  File "/usr/lib/python2.7/json/__init__.py", line 339, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 364, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
TypeError: expected string or buffer

关于如何解决此问题的任何建议 error.I 甚至尝试将 m 转换为 int 但它给出了另一个错误。

int(m)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '44d88612fea8a8f36de82e1278abb02f'

P.S：ElasticSearch 服务已启动并且运行。

Answer 1

问题与id无关。问题是 "json_data"。它是一个文件流，因此您需要 json.load 而不是 es.index

中的 json.load

ElasticSearch : TypeError: expected string or buffer?

ElasticSearch : TypeError: expected string or buffer?

python

json

python-2.7

elasticsearch

kibana