日期格式无法正常工作

Question

我正在提交一个包含日期范围选择器的表单。

我有从表单中获取选择器值的代码，格式如下：

01/03/2017 - 01/03/2017

我也有它，所以它将日期范围分成两个变量。

$one = 20/01/2017
$two = 13/03/2017

我现在正在尝试将这些变量的日期格式化为 MYSQL 使用的格式。

我的问题是结束日期会失败并一直显示为 1970-01-01。

// Get the range from the form
$daterange = $_POST["daterange"];

// Split the range into a start and end date
list($one, $two) = explode("-", "$daterange", 2);

// Test the split worked
echo $one;
echo $two;

// Format the start date into MySQL style
$StartDate = date("Y-m-d", strtotime($one));

// Test date
echo $StartDate;

// Format the end date into MySQL style
$EndDate = date("Y-m-d", strtotime($two));

//Test date
echo $EndDate;

Answer 1

试试这个：

$one = '20/01/2017';
$one = str_replace('/', '-', $one);
echo date('Y-m-d', strtotime($one));

// 输出：2017-01-20

Working Code

For the reason, see The PHP Manual for strtotime() Specifically this note

Note: Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. If, however, the year is given in a two digit format and the separator is a dash (-, the date string is parsed as y-m-d.

To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.

Answer 2

用这个来格式化你的日期：

$StartDate = date_format(date_create_from_format('d/m/Y', $one), 'Y-m-d');

反转：

$reverse = date('d/m/Y', strtotime($StartDate));

Answer 3

就我个人而言，我更喜欢不预设任何东西的date_create_from_format。

一行：

$StartDate = date_create_from_format( "d/m/Y" , $one )->format("Y-m-d");

日期格式无法正常工作

Date format not working correctly

php

mysql

date

strtotime