在 swift 中调用 class 方法
Calling class method in swift
我创建了一个小程序,它接收一个人的姓名、性别和竞技场点数,然后根据用户的性别/等级打印出一条消息。
一切正常,直到我调用我的方法,我可以看到 kemkoi 收到了值:"kemkoi", "male" and "2500"
但每当我调用我的方法时,它只显示 "()"
代码如下:
class Player {
var name : String
var gender : String
var arenaPoints : Int
// method
func getPlayerStats() {
if(gender != "male" || gender != "female") {
println("Please choose a gender!")
} else if(arenaPoints < 2000) {
println("Seems like you're too unexperienced \(arenaPoints) rating is not enough, come back when you have over 2.2k!")
} else {
println("Hello, \(name). You've chosen to play as a \(gender) and your arena points are equal to: \(arenaPoints)")
}
}
// initializer
init(name : String, gender : String, arenaPoints : Int) {
self.name = name
self.gender = gender
self.arenaPoints = arenaPoints
}
}
var kemkoi = Player(name: "kemkoi", gender: "male", arenaPoints: 2500)
println( kemkoi.getPlayerStats() )
通过执行 println( kemkoi.getPlayerStats() )
,您将打印 kemkoi.getPlayerStats()
的结果,即 nil。
试着直接调用 kemkoi.getPlayersStats()
另请注意,该方法将始终输出 Please choose a gender!
,因为您正在执行 OR,您应该改用 AND:
if(gender != "male" && gender != "female")
我创建了一个小程序,它接收一个人的姓名、性别和竞技场点数,然后根据用户的性别/等级打印出一条消息。
一切正常,直到我调用我的方法,我可以看到 kemkoi 收到了值:"kemkoi", "male" and "2500"
但每当我调用我的方法时,它只显示 "()"
代码如下:
class Player {
var name : String
var gender : String
var arenaPoints : Int
// method
func getPlayerStats() {
if(gender != "male" || gender != "female") {
println("Please choose a gender!")
} else if(arenaPoints < 2000) {
println("Seems like you're too unexperienced \(arenaPoints) rating is not enough, come back when you have over 2.2k!")
} else {
println("Hello, \(name). You've chosen to play as a \(gender) and your arena points are equal to: \(arenaPoints)")
}
}
// initializer
init(name : String, gender : String, arenaPoints : Int) {
self.name = name
self.gender = gender
self.arenaPoints = arenaPoints
}
}
var kemkoi = Player(name: "kemkoi", gender: "male", arenaPoints: 2500)
println( kemkoi.getPlayerStats() )
通过执行 println( kemkoi.getPlayerStats() )
,您将打印 kemkoi.getPlayerStats()
的结果,即 nil。
试着直接调用 kemkoi.getPlayersStats()
另请注意,该方法将始终输出 Please choose a gender!
,因为您正在执行 OR,您应该改用 AND:
if(gender != "male" && gender != "female")