如果条件为真运行一些包含 yml 文件

Question

我有一些 ubuntu 和 centos 的剧本，我想用 main.yml 来检查 when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'、运行剧本（一些 ans many :-)).

当我运行只是：

-include: centos-xxx.yml
-include: centos-xaa.yml
-include: centos-xsss.yml

它将运行所有

基本上，如果满足条件，我希望剧本运行。

我没有找到任何说明如何运行包含的文档：如果可能，我尽量不为每个包含创建任务。

Answer 1

您可以使用 when conditional 来包含文件。事实上，这有点常见。

- include: centos-xxx.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: debian-xxx.yml
  when: ansible_distribution == 'Debian'

根据您的评论 - 如果您想运行按顺序排列它们，您有两种选择。这是直截了当的：

- include: centos-a.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: centos-b.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: centos-c.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'
- include: centos-d.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'

或者，您可以这样做：

- include: centos.yml
  when: ansible_os_family == 'RedHat' or ansible_distribution == 'Centos'

和内部 centos.yml:

- include: centos-a.yml
- include: centos-b.yml
- include: centos-c.yml
- include: centos-d.yml

如果条件为真 运行 一些包含 yml 文件

If condition is true run some include yml files

ansible

如果条件为真运行一些包含 yml 文件