将具有 ASCII 值的字符串存储到数组中并使用 RSA 密钥

Question

我对编码还很陌生。我正在尝试接受用户输入，将他们的文本更改为 ASCII 值，然后使用我创建的 RSA 密钥对其进行加密。目前我有这个代码：

public class RSA {

  public static void main(String args[]){
    int p = 11; 
    int q = 17;
    int n = p*q; //187
    int phi = (p-1)*(q-1); //160
    int e = 7;
    int d = 23; 

    Scanner input = new Scanner(System.in);
    System.out.println("Please enter your message: ");
    String clearMsg = input.nextLine();
    String trimmedClearMsg = new String(clearMsg.trim());

    StringBuilder sb = new StringBuilder(); 
    for (char c : trimmedClearMsg.toCharArray())
      sb.append(String.format("%03d",(int)c));
    BigInteger asciiMsg = new BigInteger(sb.toString());

    System.out.println(asciiMsg); /*i print this out to check i have transferred to ASCII */

    byte[] asciiArray = asciiMsg.toByteArray(); 
    for (int i = 0; i < asciiArray.length; i++) {
      double keyCipher = Math.pow(i, e)%n;
      System.out.println(keyCipher);
    }
  }

当前输出为：请输入您的留言：你好 104101108108111（这是 hello 的 ASCII 值） 0.0 1.0 128.0 130.0 115.0 146.0

我不确定为什么要打印这些数字，我期待 104101108108111 的加密版本。

任何指导将不胜感激！！ :)

Answer 1

这有效（假设您的 RSA 详细信息正确）：

public class RSA {

  public static void main(String args[]) {
    int p = 11, q = 17;
    int n = p * q; //187
    int phi = (p - 1) * (q - 1); //160
    int e = 7, d = 23;

    Scanner input = new Scanner(System.in);
    System.out.print("Please enter your message: ");
    String msg = input.nextLine().trim();

    byte[] msgBytes = msg.getBytes();
    byte[] encryptedBytes = new byte[msgBytes.length];

    for (int i = 0; i < msgBytes.length; i++) {
        //below works only because n==187
        encryptedBytes[i] = (byte) (Math.pow(msgBytes[i], e) % n);
    }

    System.out.println("Encrypted string        : " + new String(encryptedBytes));
    System.out.println("Encrypted string base64 : " + new String(Base64.getEncoder().encode(encryptedBytes)));
  }
}

请注意它使用 Base64 从 Java 8 开始可用。

将具有 ASCII 值的字符串存储到数组中并使用 RSA 密钥

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