将 String 从 Broadcastreceiver 传递给 MainActivity 并将其放入 Fragment

Question

我必须将一个字符串从 Broadcastreceiver 传递到 MainActivity。然后我会在 Fragment 中得到这个字符串，我该怎么做？

MyReceiver.java

public class MyReceiver extends BroadcastReceiver
{

    @Override
    public void onReceive(Context context, Intent intent)
    {
        Bus bus = new Bus();    
        bus.post(new InformationEvent("your string"));        
    }   

}

ScarsdaleHome.java（片段）

@Subscribe public void answerAvailable(InformationEvent event) {
            String yourString= event.getInf();
            Toast.makeText(getActivity(), yourString, Toast.LENGTH_LONG).show();
        }
 @Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,Bundle savedInstanceState) {
        View rootView = inflater.inflate(R.layout.scarsdale_home_activity, container, false);

            bus = new Bus();
            bus.register(this);
        return rootView;
    }

InformationEvent.java

public class InformationEvent {
    private String inf;
    public InformationEvent(String inf) {
        this.inf = inf;
    }
    public String getInf() {
        return inf;
    }
}

我尝试了所有方法但没有任何效果:(

Answer 1

有几种方法，根据您的描述，一种选择是：在 Activity 中声明广播接收器，并将值存储在也在 Activity 中的字符串变量中。然后，您可以通过片段的构造函数将 activity 中的值传递给片段的构造函数。我会将广播接收器放在片段中。

Answer 2

这没什么难的。简单的描述方式。

例如：您正在传递数据以从 A 方式广播，

在答：

   Intent intent = new Intent(getBaseContext(),
                    AlarmReceiver.class);
            intent.putExtra("alarmTitle", "Alarm at this time!");
 startActivity(intent);

在警报接收器中：

// i skipped some lines and mentioned important stuffs alone..
@Override
public void onReceive(Context context, Intent intent) {
    Intent i = new Intent(context, NotificationFragment.class);
  i.putExtra("PASSDATA","getData");
    i.putExtra(Constants.DATAS,
            intent.getExtras().getString("alarmTitle"));// this is you are  getting from previous activity
    i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    context.startActivity(i);
 }

在 NotificationFragment 中：

   Bundle bundle = getIntent().getExtras();
    if (bundle != null && bundle.containsKey(Constants.DATAS)&& bundle.containsKey("PASSDATA")) {
        String eventStrName = bundle.getString(Constants.DATAS); //
     String broadCastData=bundle.getString("PASSDATA");// 
        //now you got the datas from broadcast receiver
}

希望我涵盖了所有场景。

Answer 3

最简单的方法是使用 Square 的 Otto Library。 http://square.github.io/otto/

创建您的自定义 class

public class InformationEvent {
    private String inf;
    public InformationEvent(String inf) {
        this.inf = inf;
    }
    public String getInf() {
        return inf;
    }
}

为 BUS 创建单例

public final class BusProvider {
    private static final Bus BUS = new Bus();

    public static Bus getInstance() {
        return BUS;
    }

    private BusProvider() {
    }
}

在 BroadcastReceiver

中发布您的活动

BusProvider.getInstance().post(new InfromationEvent("your string"));

在您的 Fragment

中订阅此活动

@Subscribe public void answerAvailable(InformationEvent event) {
    String yourString = event.getInf();
}

别忘了注册

@Override
    public void onViewCreated(View view, @Nullable Bundle savedInstanceState) {
        super.onViewCreated(view, savedInstanceState);
        BusProvider.getInstance().register(this);

    }

并在您的片段中注销 BUS

@Override
public void onDestroyView() {
    super.onDestroyView();
    BusProvider.getInstance().unregister(this);
}

将 String 从 Broadcastreceiver 传递给 MainActivity 并将其放入 Fragment

Pass String from Broadcastreceiver to MainActivity and get it into a Fragment

android

android-fragments

android-broadcast