接受非数字字符的 XPath 条件

XPath condition that accepts non-numerical characters

我目前正在 SAP PI(接收方确定对象)中构建一个 XPath 条件,它应该将消息路由到接收方 1 或接收方 2。

商家发送的给定 documentID 值如下。

收件人 1 收到以下 documentID 范围内的邮件

Range: "F00" to "F99"

接收者 2 收到以下 documentID 范围内的消息

Range: "FA0" to "FZ9"

我能想到的示例条件,但不确定这是否可行或逻辑是否正确。跟进问题,greater/less 符号是否接受非数字字符?

接收器 1 的条件

(/p1:Upload/ContainerEvent[WorkAssignmentID >= F00] EX  AND /p1:Upload/ContainerEvent[WorkAssignmentID <= F99] EX ) 

接收器 2 的条件

(/p1:Upload/ContainerEvent[WorkAssignmentID >= FA0] EX  AND /p1:Upload/ContainerEvent[WorkAssignmentID <= FZ9] EX ) 

我也在考虑是否可以在XPath中使用substring。请随时提供您的意见。谢谢

此致, 查尔斯·谭

纯 XPath 1.0 解决方案:

Receiver 1 receives messages within below documentID range Range: F00 to F99

/*/Upload/ContainerEvent
               [WorkAssignmentId
                 [string-length() = 3]
                 [starts-with(., 'F')][substring(.,2,2) >= 0][99 >= substring(.,2,2)]
                ]/EX

Receiver 2 receives messages within below documentID range Range: FA0 to FZ9

/*/Upload/ContainerEvent
               [WorkAssignmentId
                   [string-length() = 3]
                   [starts-with(., 'F')] 
                   [26 > string-length(
                            translate('ABCDEFGHIJKLMNOPQRSTUVWXYZ',substring(.,2,1), ''))]
                   [substring(.,3,1) >= 0][9 >= substring(.,3,1)]
                ]/EX

这里是基于XSLT的验证:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

  <xsl:template match="/">
    <xsl:copy-of select=
    "/*/Upload/ContainerEvent
               [WorkAssignmentId
                 [string-length() = 3]
                 [starts-with(., 'F')][substring(.,2,2) >= 0][99 >= substring(.,2,2)]
                ]/EX"/>
==============================
    <xsl:copy-of select=
    "/*/Upload/ContainerEvent
               [WorkAssignmentId
                   [string-length() = 3]
                   [starts-with(., 'F')] 
                   [26 > string-length(
                            translate('ABCDEFGHIJKLMNOPQRSTUVWXYZ',substring(.,2,1), ''))]
                   [substring(.,3,1) >= 0][9 >= substring(.,3,1)]
                ]/EX"/>

  </xsl:template>
</xsl:stylesheet>

当此转换应用于以下 XML 源文档时(提供none):

<p1>
    <Upload>
        <ContainerEvent>
            <WorkAssignmentId>F13</WorkAssignmentId>
            <EX>F13</EX>
        </ContainerEvent>
        <ContainerEvent>
            <WorkAssignmentId>F99</WorkAssignmentId>
            <EX>F99</EX>
        </ContainerEvent>
        <ContainerEvent>
            <WorkAssignmentId>E15</WorkAssignmentId>
            <EX>E15</EX>
        </ContainerEvent>
        <ContainerEvent>
            <WorkAssignmentId>FA7</WorkAssignmentId>
            <EX>FA7</EX>
        </ContainerEvent>
        <ContainerEvent>
            <WorkAssignmentId>FZ9</WorkAssignmentId>
            <EX>FZ9</EX>
        </ContainerEvent>
        <ContainerEvent>
            <WorkAssignmentId>FAB</WorkAssignmentId>
            <EX>FAB</EX>
        </ContainerEvent>
    </Upload>
</p1>

想要的结果产生了:

<EX>F13</EX>
<EX>F99</EX>
==============================
<EX>FA7</EX>
<EX>FZ9</EX>

回答您的后续问题 ("does greater/less than signs accept non-numerical characters?"):在 XPath 1.0 中,不,greater-than/less-than 仅对数字进行操作。这在 XPath 2.0 中发生了变化。