将许多参数传递给 python 中的输入 3. 猜数字游戏

Question

我刚开始在 Python 学习编程，读的是 Michael Dawson 的书，但想不出解决练习题的方法。它应该是一个 'guess a number' 游戏，计算机会尝试猜测我选择的数字。

import random
print("Pick any number between 1-100 and I'll try to guess it")
x = 1
y = 100
tries = 0
answer = "whatever"

while answer != "yes":
guess = random.randint(x, y)
answer = input("Is your number ", guess, "? Or is it 'lo'wer or 'hi'gher?")
if answer == "hi":
    x = guess + 1
if answer == "lo":
    y = guess - 1
tries += 1

print ("Got it! Your number is ", los, "! It took me ", tries, " Tries! :)")
input("End")

如您所料，这就是 python 给我的反馈：

Traceback (most recent call last):
File "/home/Documents/python/numbers.py", line 11, in <module>
answer = input("Is your number ", guess, "? Or is it 'lo'wer or 'hi'gher?")
TypeError: input expected at most 1 arguments, got 3

所以我知道我不应该期望input 接受超过 1 个参数，但我真的不知道该怎么做。对解决方案的任何友好踢将不胜感激:)

Answer 1

input 需要文档中提到的单个字符串

If the prompt argument is present, it is written to standard output without a trailing newline.

改用format

answer= input("Is your number {}? Or is it 'lo'wer or 'hi'gher?".format(guess))

Answer 2

您可以在输入上方添加一行并稍微更改输入函数调用。

import random
print("Pick any number between 1-100 and I'll try to guess it")
x = 1
y = 100
tries = 0
answer = "whatever"

while answer != "yes":
  guess = random.randint(x, y)
  input_message = "Is your number ", guess, "? Or is it 'lo'wer or 'hi'gher?"
  answer = input(input_message)

  if answer == "hi":
    x = guess + 1
  if answer == "lo":
    y = guess - 1
  tries += 1

print ("Got it! Your number is ", los, "! It took me ", tries, " Tries! :)")
input("End")

将许多参数传递给 python 中的输入 3. 猜数字游戏

Passing many arguments to input in python 3. Number guessing game

python

error-handling

python-3.x