PHP 关闭 while 循环时在关闭标记外并使用 Html 时出错

Question

我搜索并偶然发现了很多这样的问题。但这并没有回答我的问题。因此，我在这里再次询问。这是我的 php 代码：

<?php
    include("connect.php");
    if(isset($_GET['view'])) {
        $query = "SELECT * FROM posts order by 1 DESC";
        $run = mysqli_query($con, $query);

        while(mysqli_fetch_array($run)) {
        $id = $row['Post_id'];
        $title = $row['Post_title'];
        $date = $row['Post_date'];
        $author = $row['Post_author'];
        $content = $row['Post_content'];
?>
    <table width="800" align="center" border="5">
            <tr>
                   <td align="center" colspan="9"><h1>View all Posts</h1></td>
            </tr>
                </table>
   <?php
        } 
   } 
   ?>

问题出在最后一行<?php } } ?>我跟随的讲师就是这样做的。他的代码运行良好。但是我的报错，"Undefined variable row at line 27, 28, 29, 30"。任何帮助将不胜感激。

Answer 1

您需要在 while 循环中定义 $row 以迭代查询中的每条记录：

while($row = mysqli_fetch_array($run)) {
    // Do something
}

Answer 2

只是改变

 while($row = mysqli_fetch_array($run)) {

//Code
}

Answer 3

您应该定义 $row 变量。

<?php
    include("connect.php");
        if(isset($_GET['view'])) {
            $query = "SELECT * FROM posts order by 1 DESC";
            $run = mysqli_query($con, $query);

            while($row = mysqli_fetch_array($run)) {
            $id = $row['Post_id'];
            $title = $row['Post_title'];
            $date = $row['Post_date'];
            $author = $row['Post_author'];
            $content = $row['Post_content'];
        ?>

    <table width="800" align="center" border="5">
            <tr>
                   <td align="center" colspan="9"><h1>View all Posts</h1></td>
            </tr>
                </table>
                            <?php } } ?>

Answer 4

试试这个

<?php
    include("connect.php");
    if(isset($_GET['view'])) {
        $query = "SELECT * FROM posts order by 1 DESC";
        $run = mysqli_query($con, $query);

        while($row =mysqli_fetch_array($run)) {
        $id = $row['Post_id'];
        $title = $row['Post_title'];
        $date = $row['Post_date'];
        $author = $row['Post_author'];
        $content = $row['Post_content'];
?>
    <table width="800" align="center" border="5">
            <tr>
                   <td align="center" colspan="9"><h1>View all Posts</h1></td>
            </tr>
                </table>
   <?php
        } 
   } 
   ?>

Answer 5

是的。因为你没有定义数组$row。你必须定义 $行=数组（）；在使用它之前。如下所示

<?php
    include("connect.php");
        if(isset($_GET['view'])) {
            $query = "SELECT * FROM posts order by 1 DESC";
            $run = mysqli_query($con, $query);
             $row= array();
            while($row = mysqli_fetch_array($run)) {
            $id = $row['Post_id'];
            $title = $row['Post_title'];
            $date = $row['Post_date'];
            $author = $row['Post_author'];
            $content = $row['Post_content'];
        ?>
<table width="800" align="center" border="5">
            <tr>
                   <td align="center" colspan="9"><h1>View all Posts</h1></td>
            </tr>
                </table>
                            <?php } } ?>

这应该适合你。

Answer 6

定义 $row 变量。

while($row=mysqli_fetch_array($run))

PHP 关闭 while 循环时在关闭标记外并使用 Html 时出错

PHP errors when closing while loop outside closing tag and using Html alongside

php

while-loop