PyQt5 无法访问另一个 class 函数

Question

无法访问外部 class 函数，很高兴收到一些建议或解决方案我如何才能访问 Python 中的另一个 class 方法。

from PyQt5 import QtCore, QtGui, QtWidgets

class Ui_MainWindow(object):

    def setupUi(self, MainWindow):

        MainWindow.setObjectName("MainWindow")
        MainWindow.resize(480, 640)
        self.centralwidget = QtWidgets.QWidget(MainWindow)
        self.centralwidget.setObjectName("centralwidget")

        self.pushButton = QtWidgets.QPushButton(self.centralwidget)
        self.pushButton.setGeometry(QtCore.QRect(320, 520, 114, 32))
        self.pushButton.setObjectName("pushButton")
        #self.pushButton.clicked.connect(self.btnCheck)

        self.pushButton_2 = QtWidgets.QPushButton(self.centralwidget)
        self.pushButton_2.setGeometry(QtCore.QRect(190, 520, 114, 32))
        self.pushButton_2.setObjectName("pushButton_2")

        self.label = QtWidgets.QLabel(self.centralwidget)
        self.label.setGeometry(QtCore.QRect(40, 150, 411, 311))
        font = QtGui.QFont()
        font.setPointSize(66)
        self.label.setFont(font)
        self.label.setAlignment(QtCore.Qt.AlignCenter)
        self.label.setObjectName("label")

        MainWindow.setCentralWidget(self.centralwidget)
        self.statusbar = QtWidgets.QStatusBar(MainWindow)
        self.statusbar.setObjectName("statusbar")
        MainWindow.setStatusBar(self.statusbar)

        self.retranslateUi(MainWindow)
        QtCore.QMetaObject.connectSlotsByName(MainWindow)

    def retranslateUi(self, MainWindow):
        _translate = QtCore.QCoreApplication.translate
        MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow"))
        self.pushButton.setText(_translate("MainWindow", "PushButton1"))
        self.pushButton_2.setText(_translate("MainWindow", "PushButton2"))
        self.label.setText(_translate("MainWindow", "TextLabel"))

class Ui_Support(object):

    def __init__(self):
        self.ui = Ui_MainWindow()
        self.ui.setupUi(self)

    def btnCheck(self):
        self.ui.label.setText(a)

    def closeBtn(self):
        QtCore.QCoreApplication.instance().quit()

if __name__ == "__main__":
    import sys
    app = QtWidgets.QApplication(sys.argv)
    MainWindow = QtWidgets.QMainWindow()
    ui = Ui_MainWindow()
    ui.setupUi(MainWindow)
    MainWindow.show()
    sys.exit(app.exec_())

这是我的测试表单，我想从另一个 class 调用按钮事件，从内部 class 函数调用它很容易，但最好在另一个中包含多个函数class，感谢您的回复！

Answer 1

setupUi() 函数需要类型为 QMainWindow 的对象，在您的情况下，最佳选择是 Ui_Support 应该继承自 QMainWindow。

class Ui_Support(QtWidgets.QMainWindow):

    def __init__(self):
        QtWidgets.QMainWindow.__init__(self, parent=None)
        self.ui = Ui_MainWindow()
        self.ui.setupUi(self)
        self.ui.pushButton.clicked.connect(self.btnCheck)

    def btnCheck(self):
        self.ui.label.setText("a")

    def closeBtn(self):
        QtCore.QCoreApplication.instance().quit()


if __name__ == "__main__":
    import sys
    app = QtWidgets.QApplication(sys.argv)
    MainWindow = Ui_Support()
    MainWindow.show()
    sys.exit(app.exec_())

PyQt5 无法访问另一个 class 函数

PyQt5 Got stuck with access to another class function

python

pyqt

qt-designer

qmainwindow

pyqt5