GUI 必须等到启动画面完成执行

Question

我有一个 SplashScreen class，它显示一个图像和一个进度条，直到一些数据库被初始化。我希望在启动画面结束后打开一个新的 window。我有以下代码：

主要class

public class Gui{

private static final String IMG_PATH = "../opt/images/splashscreendef.jpg";

public static void main(String[] args) throws ClassNotFoundException,
        InstantiationException, IllegalAccessException,
        UnsupportedLookAndFeelException {
    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
    SwingUtilities.invokeLater(new Runnable() {
        public void run() {
            Gui ui = new Gui();
        }
    });
}

private inTouchGui() {
    InitSplashScreen splash = null;
    splash = new InitSplashScreen();
    try {
        splash.initUI();
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    BufferedImage img = null;
    try {
        img = ImageIO.read(new File(IMG_PATH));
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    ImageIcon icon = new ImageIcon(img);
    JLabel label = new JLabel(icon);
    JOptionPane.showMessageDialog(null, label);
}

}

启动画面class

public class InitSplashScreen {
private JDialog dialog;
private JProgressBar progress;

public void initUI() throws MalformedURLException {
    showSplashScreen();
    SwingWorker<Void, Integer> worker = new SwingWorker<Void, Integer>(){

        @Override
        protected Void doInBackground() throws Exception {
            Thread thread = new Thread(new InitProcess());
            thread.start();
            int i = 0;
            while (thread.isAlive()){
                i++;
                Thread.sleep(200);// Loading of databases
                publish(i);// Notify progress
            }
            if (i < 10){
                for (i = 0; i < 100; i++){
                    Thread.sleep(50);// We simulate loading even if database is fully loaded
                    publish(i);// Notify progress
                }
            }
            return null;
        }

        @Override
        protected void process(List<Integer> chunks) {
            progress.setValue(chunks.get(chunks.size() - 1));
        }

        @Override
        protected void done() {
            hideSplashScreen();
        }

    };
    worker.execute();
}



protected void hideSplashScreen() {
    dialog.setVisible(false);
    dialog.dispose();
}

protected void showSplashScreen() throws MalformedURLException {
    dialog = new JDialog((Frame) null);
    dialog.setModal(false);
    dialog.setUndecorated(true);
    JLabel background = new JLabel(new ImageIcon("splashscreendef.jpg"));
    background.setLayout(new BorderLayout());
    dialog.add(background);
    progress = new JProgressBar();
    background.add(progress, BorderLayout.SOUTH);
    dialog.pack();
    dialog.setLocationRelativeTo(null);
    dialog.setVisible(true);
}

}

当我运行我同时获得初始屏幕和图像 window 的代码时，我尝试使用 worker.get() 但屏幕上什么也没有出现。你能给我一些建议吗？我是 Java Swing 的新手。

顺便说一下，是否有可能（可能意味着不是疯狂的代码负载和时间来让它工作）像这样实现登录 window，例如？

http://designsparkle.com/wp-content/uploads/2014/06/a-simple-html-css-login-for.jpg

谢谢指教。

Answer 1

改变你的思维方式

初始化并显示启动画面，完成后，初始化并显示 Gui

这将需要一些方法来告诉谁初始化了初始屏幕它已经完成，为此，您可以使用 PropertyChangeListener...

public class InitSplashScreen {
    //...
    public void initUI(PropertyChangeListener listener) throws MalformedURLException {
        showSplashScreen();
        SwingWorker<Void, Integer> worker = new SwingWorker<Void, Integer>() {
            //...
        };
        worker.addPropertyChangeListener(listener);
        worker.execute();
    }

然后您监听 state 更改属性并检查工作状态...

public static void main(String[] args) throws ClassNotFoundException,
                InstantiationException, IllegalAccessException,
                UnsupportedLookAndFeelException {
    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
    SwingUtilities.invokeLater(new Runnable() {
        public void run() {
            InitSplashScreen splashScreen = new InitSplashScreen();
            try {
                splashScreen.initUI(new PropertyChangeListener() {
                    @Override
                    public void propertyChange(PropertyChangeEvent evt) {
                        String name = evt.getPropertyName();
                        if ("state".equalsIgnoreCase(name)) {
                            SwingWorker worker = (SwingWorker) evt.getSource();
                            if (worker.getState().equals(SwingWorker.StateValue.DONE)) {
                                Gui ui = new Gui();
                            }
                        }
                    }
                });
            } catch (MalformedURLException ex) {
                ex.printStackTrace();
            }
        }
    });
}

但请记住，您需要从 Gui 代码中删除启动画面。

您还可以使用它来 "get" SwingWorker 中 Gui 可能需要的任何信息，并将其作为参数传递给构造函数或根据您的需要通过设置器传递

另外，对我来说，这...

Thread thread = new Thread(new InitProcess());
thread.start();

在 SwingWoker 内做这件事看起来很奇怪。如果您不知道需要多少工作，您可以简单地将 JProgressBar 保持在 indeterminate 模式

GUI 必须等到启动画面完成执行

GUI has to wait until splashscreen finishes executing

java

concurrency

swing

swingworker

主要class

启动画面class