异常值:上下文必须是字典而不是 WSGIRequest

Exception Value: context must be a dict rather than WSGIRequest

我正在使用 Django 1.11、Apache 2.2 和 mod_wsgi 制作一个网络应用程序,所有这些都使用 Python 2.7。我在呈现我的页面时遇到问题。 完整的追溯是,

Environment:


Request Method: GET
Request URL: http://website.com/~user/irtf/

Django Version: 1.11.1
Python Version: 2.7.13
Installed Applications:
['irtf.apps.IrtfConfig',
 'django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'mod_wsgi.server']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware']



Traceback:

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/core/handlers/exception.py" in inner
  41.             response = get_response(request)

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  187.                 response = self.process_exception_by_middleware(e, request)

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  185.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "/home/path/irtf_website/mysite/irtf/views.py" in index
  18.         return HttpResponse(template.render(request))

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/template/backends/django.py" in render
  64.         context = make_context(context, request, autoescape=self.backend.engine.autoescape)

File "/home/path/irtf_website/mysiteenv/lib/python2.7/site-packages/django/template/context.py" in make_context
  287.         raise TypeError('context must be a dict rather than %s.' % context.__class__.__name__)

Exception Type: TypeError at /irtf/
Exception Value: context must be a dict rather than WSGIRequest.

我的views.py是,

def index(request):
        template = loader.get_template('irtf/index.html')

        return HttpResponse(template.render(request))

这可能无关紧要,但我的此页面模板仅包含文本和链接。

这是因为第一个 parameter 应该是字典。您可能将其与渲染快捷方式混为一谈

template = loader.get_template('irtf/index.html')
return HttpResponse( template.render({}, request))

要使用 render shortcut 而不是

return render(request,'irtf/index.html')