SwingWorker：令牌语法错误 "execute" -？

Question

我正在尝试使用 SwingWorker，但出于某种原因，在 worker.execute(); 我收到以下错误：

"Syntax error on token "execute", Identifier expected after this token"

这没什么帮助，这是一个一般性错误，无论它多么愚蠢，它已经折磨了我几个小时。我已经看到将 SwingWorker 移动到 class 之外的其他地方可能会修复它，但我不明白它如何以及为什么以及为什么它不应该像这样工作！呃！

public class App {

    private App() {  // CONSTRUCTOR

        final int WINHSIZE = 2000;
        final int WINVSIZE = 2000;

        class Enjoy extends JPanel  {

            @Override
            public void paintComponent(Graphics g) {
                g.drawLine(0, 0, 2000, 2000);
            }

            class MyExecutor extends SwingWorker<Void,Void> { 

                @Override
                protected Void doInBackground() {
                    return null;
                }

                @Override
                protected void done(){ // runs on EDT

                }
            }

            MyExecutor worker = new MyExecutor();
            worker.execute(); // What the hell is going wrong here?

        }

        Runnable runner = new Runnable() { 
            @Override
            public void run() {
                JFrame f = new JFrame("Title");
                JPanel panel = new Enjoy();
                JScrollPane myScrollPane = new JScrollPane(panel);
                f.add("Center", myScrollPane);
                f.pack();
                f.setVisible(true);
            }
        };

        SwingUtilities.invokeLater(runner);

    }

    public static void main(String[] args) {
        new App();
    } 
}

谢谢。

Answer 1

worker.execute();必须在某个方法里面，不能直接在你的Enjoyclass.

范围内

SwingWorker：令牌语法错误 "execute" -？

SwingWorker: Syntax error on token "execute" -?

java

swingworker