javascript 在函数外访问数组
javascript accessing array outside of function
所以我正在为免费代码训练营制作这个 twitch.tv api 页面。
我正在尝试遍历流媒体数组并将数据推送到结果数组,按观众数排序并在页面上显示结果数组中的数据。
问题是 .append 内容在 for 循环中多次写入信息。如果我将它移出 for 循环,则变量未定义。
聪明人有什么想法吗?
$(document).ready(function(){
getInfo();
var results = [];
function getInfo(){
var streamers = ["FreeCodeCamp","PlayHearthstone","summit1G","BradfordLee","Savjz","Z28RyanK"];
streamers.forEach(function(streamers){
$.getJSON('https://wind-bow.gomix.me/twitch-api/channels' + '/' + streamers + '?callback=?', function(data){
var name = data.display_name;
var game = data.game;
var logo = data.logo;
$.getJSON('https://wind-bow.gomix.me/twitch-api/streams' + '/' + streamers + '?callback=?', function(data){
var status = data.stream;
if(data.stream == undefined){
status = "Offline";
}else{
status = "Online";
}
var views = data.stream;
if(data.stream == undefined){
views = 0;
}else{
views = data.stream.viewers;
}
results.push({"name": name, "logo": logo, "status": status, "game": game, "views": views});
results.sort(function(b, a) {return parseFloat(a.views) -parseFloat(b.views);});
console.log(results);
results.forEach(function(results){
$('.main').append('<div><img src="' + logo + '"><p>' + name + '</p><p>' + status + '</p><p>' + game + '</p><p>' + views + '</p></div>');
})
} )
})
})
}
});
您可以移出追加行。你说你无权访问变量,但你只是将它们存储在 results
数组中,因此你可以从那里访问它们。所以简单地移出这条线,改变是这样的:
results.forEach(function(result){
$('.main').append('<div><img src="' + result.logo + '"><p>' + result.name + '</p><p>' + result.status + '</p><p>' + result.game + '</p><p>' + result.views + '</p></div>');
})
(请注意,您不应该 results.forEach(function(results){
使用名称 results
两次,类似于 streamers
。您是 运行 和 forEach
在 results
之上,所以每个 result
(不是复数))
下面我重写了你的一段代码,修复了一些错误。在此 fiddle.
中查看实际效果
var streamers;
var streamCallsCompleted;
var results;
$(document).ready(function() {
streamers = ["FreeCodeCamp", "PlayHearthstone", "summit1G", "BradfordLee", "Savjz", "Z28RyanK"];
results = [];
streamCallsCompleted = 0;
getAndAppendInfo(streamers);
// parseFloat shouldn't be necessary as views should be a whole number
results.sort(function(b, a) {
return parseInt(a.views) - parseInt(b.views);
});
});
function getAndAppendInfo(streamers) {
streamers.forEach(
function(streamer) {
$.getJSON('https://wind-bow.gomix.me/twitch-api/channels' + '/' + streamer + '?callback=?', function(data) {
channelCallSuccess(data, streamer)
})
.fail(channelCallError);
});
}
function channelCallError() {
streamCallsCompleted++;
checkAndAppendResults();
}
function streamCallError() {
streamCallsCompleted++;
checkAndAppendResults();
}
function channelCallSuccess(data, streamer) {
var name = data.display_name;
var game = data.game;
var logo = data.logo;
$.getJSON('https://wind-bow.gomix.me/twitch-api/streams' + '/' + streamer + '?callback=?', function(data) {
streamCallsCompleted++;
var status = data.stream ? "Online" : "Offline";
var views = data.stream ? data.stream.viewers : 0;
results.push({
"name": name,
"logo": logo,
"status": status,
"game": game,
"views": views
});
checkAndAppendResults();
});
}
function checkAndAppendResults() {
if (streamCallsCompleted < streamers.length) {
return;
}
console.log(results);
results.forEach(function(result) {
$('.main').append('<div><img src="' + result.logo + '"><p>' + result.name + '</p><p>' + result.status + '</p><p>' + result.game + '</p><p>' + result.views + '</p></div>');
});
}
基本上,这里的要点是 getJSON 调用是异步的。这意味着这段代码没有按顺序执行。因此,我们必须跟踪我们拨打了多少电话。只有当所有调用都成功或错误时,我们才会处理结果。
所以我正在为免费代码训练营制作这个 twitch.tv api 页面。 我正在尝试遍历流媒体数组并将数据推送到结果数组,按观众数排序并在页面上显示结果数组中的数据。
问题是 .append 内容在 for 循环中多次写入信息。如果我将它移出 for 循环,则变量未定义。
聪明人有什么想法吗?
$(document).ready(function(){
getInfo();
var results = [];
function getInfo(){
var streamers = ["FreeCodeCamp","PlayHearthstone","summit1G","BradfordLee","Savjz","Z28RyanK"];
streamers.forEach(function(streamers){
$.getJSON('https://wind-bow.gomix.me/twitch-api/channels' + '/' + streamers + '?callback=?', function(data){
var name = data.display_name;
var game = data.game;
var logo = data.logo;
$.getJSON('https://wind-bow.gomix.me/twitch-api/streams' + '/' + streamers + '?callback=?', function(data){
var status = data.stream;
if(data.stream == undefined){
status = "Offline";
}else{
status = "Online";
}
var views = data.stream;
if(data.stream == undefined){
views = 0;
}else{
views = data.stream.viewers;
}
results.push({"name": name, "logo": logo, "status": status, "game": game, "views": views});
results.sort(function(b, a) {return parseFloat(a.views) -parseFloat(b.views);});
console.log(results);
results.forEach(function(results){
$('.main').append('<div><img src="' + logo + '"><p>' + name + '</p><p>' + status + '</p><p>' + game + '</p><p>' + views + '</p></div>');
})
} )
})
})
}
});
您可以移出追加行。你说你无权访问变量,但你只是将它们存储在 results
数组中,因此你可以从那里访问它们。所以简单地移出这条线,改变是这样的:
results.forEach(function(result){
$('.main').append('<div><img src="' + result.logo + '"><p>' + result.name + '</p><p>' + result.status + '</p><p>' + result.game + '</p><p>' + result.views + '</p></div>');
})
(请注意,您不应该 results.forEach(function(results){
使用名称 results
两次,类似于 streamers
。您是 运行 和 forEach
在 results
之上,所以每个 result
(不是复数))
下面我重写了你的一段代码,修复了一些错误。在此 fiddle.
中查看实际效果var streamers;
var streamCallsCompleted;
var results;
$(document).ready(function() {
streamers = ["FreeCodeCamp", "PlayHearthstone", "summit1G", "BradfordLee", "Savjz", "Z28RyanK"];
results = [];
streamCallsCompleted = 0;
getAndAppendInfo(streamers);
// parseFloat shouldn't be necessary as views should be a whole number
results.sort(function(b, a) {
return parseInt(a.views) - parseInt(b.views);
});
});
function getAndAppendInfo(streamers) {
streamers.forEach(
function(streamer) {
$.getJSON('https://wind-bow.gomix.me/twitch-api/channels' + '/' + streamer + '?callback=?', function(data) {
channelCallSuccess(data, streamer)
})
.fail(channelCallError);
});
}
function channelCallError() {
streamCallsCompleted++;
checkAndAppendResults();
}
function streamCallError() {
streamCallsCompleted++;
checkAndAppendResults();
}
function channelCallSuccess(data, streamer) {
var name = data.display_name;
var game = data.game;
var logo = data.logo;
$.getJSON('https://wind-bow.gomix.me/twitch-api/streams' + '/' + streamer + '?callback=?', function(data) {
streamCallsCompleted++;
var status = data.stream ? "Online" : "Offline";
var views = data.stream ? data.stream.viewers : 0;
results.push({
"name": name,
"logo": logo,
"status": status,
"game": game,
"views": views
});
checkAndAppendResults();
});
}
function checkAndAppendResults() {
if (streamCallsCompleted < streamers.length) {
return;
}
console.log(results);
results.forEach(function(result) {
$('.main').append('<div><img src="' + result.logo + '"><p>' + result.name + '</p><p>' + result.status + '</p><p>' + result.game + '</p><p>' + result.views + '</p></div>');
});
}
基本上,这里的要点是 getJSON 调用是异步的。这意味着这段代码没有按顺序执行。因此,我们必须跟踪我们拨打了多少电话。只有当所有调用都成功或错误时,我们才会处理结果。