从文件中每隔 N 个（第 8 个字符）打印一次 [Python]

Question

我从文件中转储了很长的位序列。现在，我想获取这个位序列并能够从中提取每第 8 位。例如：

100010010101000001001110010001110000110100001010
000110100000101000000000000000000000000000001101
010010010100100001000100010100100000000000000000
etc

会给出：

100110
(extraction from second line)
(extraction from third line)
etc

到目前为止我有以下代码：

 #/usr/bin/python

 with open("thebits.txt", 'r') as f:
        content = [x.strip('\n') for x in f.readlines()]
        {//logic to extract every 8th bit from each line and print it}

如何从每行中提取每第 8 位？ .

Answer 1

您可以使用简单的切片：

with open('thebits.txt', 'r') as f:
    for line in f:
        print line.strip()[7::8]

您的示例文件给出：

100110
000001
100000

切片 [7::8] 从第 8 个字符开始为您提供每第 8 个字符（7 从 0 开始索引）。

Answer 2

with open(infile) as f:
    print("".join(line[7::8] for line in f))

Answer 3

假设您想要单独的每一行：

with open('tmp.txt', 'r') as f:
    for line in f.read().splitlines():
        print(line[7::8])

从文件中每隔 N 个（第 8 个字符）打印一次 [Python]

Printing every Nth (8th character) from a file [Python]

python

file-io

loops

function