在 R 中生成多个字符的（随机）序列

Question

我可以使用

创建一个单字母序列

LETTERS[seq( from = 1, to = 10 )]
letters[seq( from = 1, to = 10 )]

我可以使用 random 包

创建各种长度的随机字符串

library(random)
string <- randomStrings(n=10, len=5, digits=TRUE, upperalpha=TRUE,
                  loweralpha=TRUE, unique=TRUE, check=TRUE)

不幸的是，我无法使用 set.seed 函数，例如 2。

有没有办法在每次运行R 文件时创建相同（随机）的（唯一）字符串组合？

我的结果看起来像这样（每次我运行函数的结果都一样）：

       V1     
  [1,] "k7QET"
  [2,] "CLlWm"
  [3,] "yPuwh"
  [4,] "JJqEX"
  [5,] "38soF"
  [6,] "xkozk"
  [7,] "uaiOW"
  [8,] "tZcrW"
  [9,] "8K4Cc"
 [10,] "RAhuU"

Answer 1

在文件中，假设 test.R，添加以下内容

set.seed(1)
stringi::stri_rand_strings(10, 5)

那么每次都能重现

replicate(5, source("test.R", verbose = FALSE)$value)
#       [,1]    [,2]    [,3]    [,4]    [,5]    
#  [1,] "GNZuC" "GNZuC" "GNZuC" "GNZuC" "GNZuC" 
#  [2,] "twed3" "twed3" "twed3" "twed3" "twed3"
#  [3,] "CAgNl" "CAgNl" "CAgNl" "CAgNl" "CAgNl"
#  [4,] "UizNm" "UizNm" "UizNm" "UizNm" "UizNm" 
#  [5,] "vDe7G" "vDe7G" "vDe7G" "vDe7G" "vDe7G"
#  [6,] "N0NrL" "N0NrL" "N0NrL" "N0NrL" "N0NrL"
#  [7,] "TbUBp" "TbUBp" "TbUBp" "TbUBp" "TbUBp"
#  [8,] "fn6iP" "fn6iP" "fn6iP" "fn6iP" "fn6iP" 
#  [9,] "oemYW" "oemYW" "oemYW" "oemYW" "oemYW"
# [10,] "m1Tjg" "m1Tjg" "m1Tjg" "m1Tjg" "m1Tjg"

作为 source() 的替代方法，您可以在那里使用 parse()。

replicate(5, eval(parse("test.R")))

Answer 2

基于 R 的替代解决方案：

set.seed(1)
result <- rawToChar(as.raw(sample(c(65:90,97:122), 5, replace=T)))

受此答案启发 post：

在 R 中生成多个字符的（随机）序列

Generating a (random) sequence of multiple characters in R

random

r