Python 输入行将不会获得键盘输入 - 而是在终端中输入

Question

过去几周我一直在做一个项目，通过 Raspberry Pi 和 python 通过无线连接和使用 REST 协议与工业机器人进行交互。我是 python 的新手，但熟悉 C++，所以我对编程并不陌生。

我已经在 python 中使用 Tkinter 创建了一个 GUI（已经感谢您的大量帮助），并且我正在尝试创建一种信息亭模式。我已经让 GUI 启动全屏，但没有关闭它的选项。我坚持的是，我试图在我的 GUI 中的一个弹出窗口 windows 中创建一个输入行，当输入正确的密码字符串时，它将关闭 GUI 以供管理员或授权人员使用如果需要，访问 Raspberry Pi 文件的其余部分。我相信我知道如何使用 root.quit() 方法（父 window 是根）使这个过程工作，但输入行甚至不会显示任何文本。我输入的所有文本都是在终端中输入的，即使我的 GUI 是全屏的。这是代码的特定部分，其中包含我试图让输入行位于的弹出窗口 window 的注释：

################## Status Window ##################
def statusWindow():                                                     #defines function for popup window for additional options
    window = Toplevel(root)                                             #creates variable to place widgets in window
    window.title('Status')                                              #makes window title for specific window frame
    w, h = window.winfo_screenwidth(), window.winfo_screenheight()      #aquires dimensions from display size
    window.geometry("%dx%d+0+0" % (w, h))                               #sets window size to aquired dimensions
    window.overrideredirect(True)                                       #removes top bar and exit button from parent window frame

    batteryButton = Button(window, text="Battery", fg="green", command=lambda: showBattery(window), width=35, height=12)        #defines criteria for battery button in new window
    statusButton = Button(window, text="Overview", fg="green", command=lambda: showQueueStatus(window), width=35, height=12)    #defines criteria for status button in new window
    returnButton = Button(window, text="Return...", fg="green", command=window.destroy, width=35, height=12)                    ##defines criteria for return button in new window
    passEntry = Entry(window, show="*")

    batteryButton.grid(row=1, column=0, padx=10, pady=5)        #makes button viewable in specified orientation                                                                
    statusButton.grid(row=2, column=0, padx=10, pady=5)         #makes button viewable in specified orientation
    returnButton.grid(row=3, column=0, padx=10, pady=5)         #makes button viewable in specified orientation
    passEntry.grid(row=4, columnspan=10, sticky=W)

    robotName(window)       #call robotName function to display robot name
    winReturn(window)       #call winReturn function to create return label

def robotName(winFrame):                                #define function to display robot name in status window
    label = Label(winFrame, text="Robot Name: ")        #defines variable label for visual display
    name = robot.robot_name()                           #gets robot name from robot and stores it in name variable
    nameLabel = Label(winFrame, text=name)              #defines variable label for visual to hold robot name as string        

    label.grid(row=0, column=0, padx=10, pady=5)        #makes label display in popup window
    nameLabel.grid(row=0, column=3, padx=10, pady=5)    #makes robot name display in popup window

def showBattery(winFrame):                                  #define function to display current battery percentage in popup window
    battery = robot.battery_percentage()                    #retrieves current battery status from robot and stores it in battery variable
    battery = str(battery) + '%'                            #redefines battery variable as previous battery variable string with percentage
    batteryLabel = Label(winFrame, text=battery)            #defines battery label with specified criteria
    batteryLabel.grid(row=1, column=3, padx=10, pady=5)     #displays battery label in popup window

def showQueueStatus(winFrame):                              #define function to display current robot mission queue item status
    queue = robot.robot_state_text()                        #retrieves current queue item status and stores in queue variable
    qStatusLabel = Label(winFrame, text=queue)              #defines queue status label with specified criteria
    qStatusLabel.grid(row=2, column=3, padx=10, pady=5)     #displays queue status label in popup window

def winReturn(winFrame):                                        #define function to display label for return button
    returnLabel = Label(winFrame, text="Close out of window")   #defines return label with specified criteria
    returnLabel.grid(row=3, column=3, padx=10, pady=5)          #displays return label in popup window

我已将入口行放在 statusWindow() 定义中，因为这是从我的程序的其余部分调用的方法。如果您对为什么不让我输入输入行有任何想法，我们将不胜感激。如果需要我的代码的更多示例，我可以 post 更多，但我试图让这个 post 简短。

Answer 1

你可以做一个

passEntry.bind('<Return>', myfunc)

调用密码检查功能，决定要做什么等。如果您需要隐藏全屏 gui，请尝试

root.tk.call('wm', 'withdraw', root)

Answer 2

如果不了解您的程序是如何工作的，您实际上不需要创建顶层 window 来请求管理员访问权限。您可以使用 tkinters simpledialog askstring 函数要求输入密码，然后使用 iconify() 最小化 window.

看看这个例子。

from tkinter import *
from tkinter import simpledialog
# from Tkinter import * # for python 2.x
# import tkSimpleDialog as simpledialog # for python 2.x

root = Tk()
root.attributes("-fullscreen", True)# fullscreen without the standard window buttons

def check_admin_password():
    # use askstring here to verify password.
    pass_attempt = simpledialog.askstring("Verifying access",
                                           "Please enter Admin password")
    if pass_attempt == "password":
        root.iconify() # used whatever your instance of Tk() is here in place of root.

admin_minimize_button = Button(root, text = "Minimize window", command = check_admin_password)
admin_minimize_button.pack()

root.mainloop()

Python 输入行将不会获得键盘输入 - 而是在终端中输入

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