使用谓词 iOS SDK 从字典数组中过滤数据

Question

大家好，我有一个字典数组，你们能告诉我如何根据字典键过滤这些数据吗？

(
    {
    "mall_id" = M0550;
    "mall_name" = "Amrita Shopping Complex";
},
    {
    "mall_id" = M0509;
    "mall_name" = "Ashoka Market";
},
    {
    "mall_id" = M0943;
    "mall_name" = "Biju Pattnaik Commercial Complex";
},
    {
    "mall_id" = M0457;
    "mall_name" = "BMC Bhawani Mall";
},
    {
    "mall_id" = M0460;
    "mall_name" = "BMC Keshari Mall";
},
    {
    "mall_id" = M0571;
    "mall_name" = "BMC Market Complex";
},
    {
    "mall_id" = M0453;
    "mall_name" = "Forum Mart";
},
    {
    "mall_id" = M0609;
    "mall_name" = "Indradhanu Market";
},
    {
    "mall_id" = M0558;
    "mall_name" = "Kalyani Plaza Market Complex";
},
    {
    "mall_id" = M0463;
    "mall_name" = "Maa Barabhuja Mall";
},
    {
    "mall_id" = M0553;
    "mall_name" = "Mahaveer Complex";
},
    {
    "mall_id" = M0570;
    "mall_name" = "Market Building";
},
    {
    "mall_id" = M0452;
    "mall_name" = "Pal Heights Mall";
},
    {
    "mall_id" = M0466;
    "mall_name" = "Priyadarshini Market Complex";
},
    {
    "mall_id" = M0677;
    "mall_name" = "Ruchika Market";
},
    {
    "mall_id" = M0504;
    "mall_name" = "Shubham Market Complex";
},
    {
    "mall_id" = M0564;
    "mall_name" = "Subhadra Complex";
},
    {
    "mall_id" = M0559;
    "mall_name" = "Sultania Shopping Complex";
},
    {
    "mall_id" = M0552;
    "mall_name" = "Tathastu Complex";
},
    {
    "mall_id" = M0568;
    "mall_name" = "Western Tower Market Building";
}
)

我想要实现的目标，每当我在搜索栏中输入任何内容时，它都会检查 mall_name 键和 return 数组中的匹配值。

感谢和问候

Answer 1

这为您提供了一组只有 requiredMallID

的字典

 NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", requiredMallID]];

例如，

NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", "M0550"]];

给你

    (
        {
        "mall_id" = M0550;
        "mall_name" = "Amrita Shopping Complex";
    } 
)

Answer 2

这将为您提供所需的输出

Objective - C

NSArray *filteredData = [yourArrayContainingDictionary filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]];

Swift

let filteredData = yourArrayContainingDictionary.filter{
    let string = [=11=]["mall_name"] as! String

    return string.hasPrefix("searchText")
}

希望对您有所帮助:)

Answer 3

NSArray *filtered = [arrName filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name == %@)", requiredMailName]];

Answer 4

试试这个。（谓词的工作方式类似于 SQL 查询）

对象 C

 NSArray *filterArray = [sourceArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]];

Swift

var filterArray: [Any] = sourceArray.filter { NSPredicate(format: "(mall_name contains[c] %@)", searchText).evaluate(with: [=11=]) }

它将 return 个名称包含搜索字符串的条目。

Answer 5

 NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", wantedMallID]];

Answer 6

使用此解决方案

NSArray *filtered = [yourArrayOfDictionary filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", <your search text from search bar>]];

Answer 7

这是我使用谓词和经典版本的 2 个版本：

let dict = [
    [
        "mall_id": 1,
        "mall_name": "Amrita Shopping Complex"
    ],
    [
        "mall_id": 2,
        "mall_name": "Ashoka Market"
    ] ]

// Example using Predicate

let mallNamePredicate = NSPredicate(format: "mall_name contains %@", "Ashoka")
let filteredWithPredicate = (dict as NSArray).filtered(using: mallNamePredicate)

// Classical filter example 
let filtered = dict.filter { pair in
    guard let mallName = pair["mall_name"] as? String else { return false }
    return mallName.hasPrefix("Ashoka")
}

Answer 8

更快捷的方法是

let mallArray  = [
    [
        "mall_id": "M0550",
        "mall_name": "Amrita Shopping Complex"
    ],
    [
        "mall_id": "M0509",
        "mall_name": "Ashoka Market"
    ]
]

func isMatching(_ searchText: String) -> [[String: Any]] {
    let filteredArray = mallArray.filter {
        return [=10=]["mall_name"]!.contains(searchText)
    }
    return filteredArray
}

let malls = isMatching("Ashoka")
print(malls)

Answer 9

他想搜索 mall_name 上的部分匹配项，而不是 mall_id，随着用户在搜索栏。所以正确的解决方案是：

[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]

... 不是 'mall_id'，不是 @"(xxx == %@)"，'contains[c]' 给了他 case-insensitive 匹配。

使用谓词 iOS SDK 从字典数组中过滤数据

Filter data from array of Dictionary using predicate iOS SDK

arrays

dictionary

objective-c

nspredicate

ios