将函数值返回为 float Python 3.6.1

Question

我收到以下错误，似乎无法弄清楚如何解决。按照逻辑，我调用 3 个函数和所有 3 个 return 值作为浮点数，然后我对存储的 returned 值执行一些数学运算并将其打印为浮点数。那么哪里出了问题呢？我为 A 面输入 4，为 B 面输入 5。

错误信息：

输入A边的长度：4.0 输入B边的长度：5.0

Traceback (most recent call last):
  File "python", line 26, in <module>
  File "python", line 9, in main
  File "python", line 24, in calculateHypotenuse
TypeError: unsupported operand type(s) for ^: 'float' and 'float'

import math

def main():
  #Call get length functions to get lengths.
  lengthAce = getLengthA()
  lengthBee = getLengthB()

  #Calculate the length of the hypotenuse
  lengthHypotenuse = calculateHypotenuse(float(lengthAce),float(lengthBee))

  #Display length of C (hypotenuse)
  print()
  print("The length of side C 'the hypotenuse' is {}".format(lengthHypotenuse))

#The getLengthA function prompts for and returns length of side A  
def getLengthA():
  return float(input("Enter the length of side A: "))

#The getLengthA function prompts for and returns length of side B
def getLengthB():
  return float(input("Enter the length of side B: "))

def calculateHypotenuse(a,b):
  return math.sqrt(a^2 + b^2)

main()

print()
print('End of program!')

Answer 1

^ in Python 是 bitwise XOR operator，不是幂运算符：

The ^ operator yields the bitwise XOR (exclusive OR) of its arguments, which must be intege

您需要改用 **，是幂运算符：

def calculateHypotenuse(a,b):
  return math.sqrt(a**2 + b**2)

将函数值返回为 float Python 3.6.1

Returning function values as float Python 3.6.1

python

math

hypotenuse

function