如何将一个或两个命名向量作为参数传递给 dplyr::recode
how to pass a named vector or two vectors as arguments to dplyr::recode
我想将一个命名向量或两个向量传递给 dplyr::recode。
假设我有:
library(dplyr)
set.seed(1)
x <- c("customer", sample(c("a", "b", "c"), 10, replace = TRUE))
recode_tbl <- tibble(letter = letters[1:3], fruit = c("apple", "banana", "cranberry"))
我想做的是使用 recode_tbl 的列重新编码 x,而无需手动指定对:
recode(x, a = "apple", b = "banana", c = "cranberry")
类似于:
recode(x, as.name(recode_tbl$letter) = recode_tbl$fruit)
这显然行不通。我不反对尝试 NSE,但如果有人能成功的话那就太好了。
谢谢。
我们可以在 base R
x1 <- unname(setNames(recode_tbl$fruit, recode_tbl$letter)[x])
x1[is.na(x1)] <- x[is.na(x1)]
或使用 do.call
和 recode
do.call(dplyr::recode, c(list(x), setNames(recode_tbl$fruit, recode_tbl$letter)))
#[1] "customer" "apple" "banana" "banana" "cranberry" "apple"
#[8] "cranberry" "cranberry" "banana" "banana" "apple"
我想将一个命名向量或两个向量传递给 dplyr::recode。 假设我有:
library(dplyr)
set.seed(1)
x <- c("customer", sample(c("a", "b", "c"), 10, replace = TRUE))
recode_tbl <- tibble(letter = letters[1:3], fruit = c("apple", "banana", "cranberry"))
我想做的是使用 recode_tbl 的列重新编码 x,而无需手动指定对:
recode(x, a = "apple", b = "banana", c = "cranberry")
类似于:
recode(x, as.name(recode_tbl$letter) = recode_tbl$fruit)
这显然行不通。我不反对尝试 NSE,但如果有人能成功的话那就太好了。
谢谢。
我们可以在 base R
x1 <- unname(setNames(recode_tbl$fruit, recode_tbl$letter)[x])
x1[is.na(x1)] <- x[is.na(x1)]
或使用 do.call
和 recode
do.call(dplyr::recode, c(list(x), setNames(recode_tbl$fruit, recode_tbl$letter)))
#[1] "customer" "apple" "banana" "banana" "cranberry" "apple"
#[8] "cranberry" "cranberry" "banana" "banana" "apple"