您将如何处理不同格式的日期?

How would you handle different formats of dates?

我有不同类型的日期格式,例如:

注意它们都是不同的格式,不同的顺序,有的有 2 个月,有的只有 1 个月,我尝试使用 moment js with no results, I also tried to use date js 还没有成功。

我尝试做一些拆分:

dates.push({
    Time : []
});

function doSelect(text) {
  return $wikiDOM.find(".infobox th").filter(function() {
    return $(this).text() === text;
  });
}
dateText = doSelect("Date").siblings('td').text().split(/\s+/g);
 for(var i = 0; i < dateText.length; i++) {
  d += dateText[i] + ' ';
}
dates[0].Time.push(d);

但结果是:

"Time": [
            "27 - 28 August 663 CE ",

最终我需要自动生成的是:

<ul class="Days">
  <li>27</li>
  <li>28</li>
</ul>

<ul class="Months">
  <li>August</li>
</ul>

<ul class="Year">
  <li>663</li>
</ul>

也想办法处理CEADBC

为了实现这一点,我想使用的理想方法是多维数组:

time.push({
    Day : [], 
    Month : [],
    Year : [],
    Prefix : []
});

可能要检查 max 2 numbers for days,对照 January, February, March.. 之类的字符串列表检查月份,然后检查最小年份 3 numbers to max 4 numbers,然后处理 prefix with some conditionals。但是,year 2 or 1 怎么样?或者日期是 02/9/1975 怎么样?或者将 dash 分开,它们将成为一种新格式。我认为逻辑有点在那里,但鉴于它们都是不同的格式,你如何按照上述将这些日期拆分为多维数组?

I will be updating this answer more and more while I will build new parsers. Feel free to contribute.

所以对于这些格式,我会这样做:

27 - 28 August 663 CE
22 August 1945 19 May
May 4 1945 – August 22 1945
5-10 February 1720

JS

months = new Set(["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]);
for(var i = 0; i < dateText.length; i++) {
  d += dateText[i] + ' ';
}
var words = d.replace("–", " ").replace("-", " ").replace(",", " ").replace("/", " ").split(' ');
words = $.grep(words, function(n, i){
    return (n !== "" && n != null);
});
var array = words;
var newArray = array.filter(function(v){return v!==''});
for (const word of newArray) {
 if (months.has(word)) {
   spacetime[0].Time.months.push(word);
 } else if (+word < 32) {
   spacetime[0].Time.days.push(+word);
 } else if (+word < 2200) {
   spacetime[0].Time.years.push(+word);
 } else if (/\w+/.test(word)) {
   spacetime[0].Time.suffixes.push(word);
}

jSon 示例:

        "Time": {
            "days": [
                22
            ],
            "months": [
                "August"
            ],
            "years": [
                1945
            ],
            "suffixes": [
                "10:25",
                "(UTC+1)"
            ]