如何在 symfony 上使用路由注释匹配 URI

Question

URI 示例： '/department/id/1'

控制器：

/**

     @Route/department/id/{slug}
*/
        function($slug)
        return new Response($slug)

它return我'1'

如果我有 URI:/department/id/1/category/id/2

如何构造捕获1和2的@Route？

请帮忙谢谢

Answer 1

/**
 @Route(/department/{slug}/category/{id}, name='department_category_detail')
*/
public function departmentCagetegoryDetailAction($slug, $id) {
    ....
}