导航到其他页面在 render() 调用中有效,但在单独的函数中无效
Navigation to other page works in render() call but not in separate function
我正在使用 react-navigation 第三方组件,这是我的代码:
import { StackNavigator } from 'react-navigation';
// ==============
// Profile Screen
// ==============
class ProfileScreen extends React.Component {
static navigationOptions = {
title: 'Profile',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Profile Page</Text>
<TouchableHighlight onPress={() => navigate('Detail')}>Next</TouchableHighlight>
</View>
);
}
onEditProfile(event) {
() => navigate('Detail');
}
}
// ==============
// Detail Screen
// ==============
class DetailScreen extends React.Component {
static navigationOptions = {
title: 'Detail',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Detail Page</Text>
</View>
);
}
}
// ==============
// Routing
// ==============
const ModelStack = StackNavigator({
Profile: { screen: ProfileScreen },
Detail: { screen: DetailScreen },
});
AppRegistry.registerComponent('ModelStack', () => ModelStack);
export default ModelStack;
在<TouchableHighlight>
的onPress事件中,有效;当我如上所示将确切内容放入 onEditProfile()
时,它不起作用。为什么?如何将动作放入函数中?
附加问题:
如何在导航(推送)到下一页时更改 "Back" 措辞? 更新:我找到了,可以通过headerBackTitle
in navigationOptions
设置
- 我可以将
ProfileScreen
& DetailScreen
class 移动到单独的 JS 文件吗?
更新:更新代码onPressEditProfile
:
onPressEditProfile(event) {
const { navigate } = this.props.navigation;
console.log('Clicked Edit Profile');
() => navigate('Detail');
}
以上代码引发了以下错误:
undefined is not an object (evaluating 'this.props.navigation')
错误行在onPressEditProfile
函数的第一行。
在函数中添加这一行
const { navigate } = this.props.navigation;
是的,你可以做到。您可以在单独的文件中为所有屏幕声明导航常量并导出该常量。然后为不同的屏幕制作不同的文件并导航到这些屏幕。
更新代码
import { StackNavigator } from 'react-navigation';
import React,{Component} from 'react';
import {
Text,
View,
TouchableHighlight,
} from 'react-native';
// ==============
// Profile Screen
// ==============
class ProfileScreen extends Component {
static navigationOptions = {
title: 'Profile',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Profile Page</Text>
<TouchableHighlight onPress={() => this.onEditProfile()}><Text>Next</Text></TouchableHighlight>
</View>
);
}
onEditProfile() {
const { navigate } = this.props.navigation;
navigate('Detail');
}
}
// ==============
// Detail Screen
// ==============
class DetailScreen extends Component {
static navigationOptions = {
title: 'Detail',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Detail Page</Text>
</View>
);
}
}
// ==============
// Routing
// ==============
const ModelStack = StackNavigator({
Profile: { screen: ProfileScreen },
Detail: { screen: DetailScreen },
});
export default ModelStack;
我正在使用 react-navigation 第三方组件,这是我的代码:
import { StackNavigator } from 'react-navigation';
// ==============
// Profile Screen
// ==============
class ProfileScreen extends React.Component {
static navigationOptions = {
title: 'Profile',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Profile Page</Text>
<TouchableHighlight onPress={() => navigate('Detail')}>Next</TouchableHighlight>
</View>
);
}
onEditProfile(event) {
() => navigate('Detail');
}
}
// ==============
// Detail Screen
// ==============
class DetailScreen extends React.Component {
static navigationOptions = {
title: 'Detail',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Detail Page</Text>
</View>
);
}
}
// ==============
// Routing
// ==============
const ModelStack = StackNavigator({
Profile: { screen: ProfileScreen },
Detail: { screen: DetailScreen },
});
AppRegistry.registerComponent('ModelStack', () => ModelStack);
export default ModelStack;
在<TouchableHighlight>
的onPress事件中,有效;当我如上所示将确切内容放入 onEditProfile()
时,它不起作用。为什么?如何将动作放入函数中?
附加问题:
如何在导航(推送)到下一页时更改 "Back" 措辞?更新:我找到了,可以通过headerBackTitle
innavigationOptions
设置
- 我可以将
ProfileScreen
&DetailScreen
class 移动到单独的 JS 文件吗?
更新:更新代码onPressEditProfile
:
onPressEditProfile(event) {
const { navigate } = this.props.navigation;
console.log('Clicked Edit Profile');
() => navigate('Detail');
}
以上代码引发了以下错误:
undefined is not an object (evaluating 'this.props.navigation')
错误行在onPressEditProfile
函数的第一行。
在函数中添加这一行
const { navigate } = this.props.navigation;
是的,你可以做到。您可以在单独的文件中为所有屏幕声明导航常量并导出该常量。然后为不同的屏幕制作不同的文件并导航到这些屏幕。
更新代码
import { StackNavigator } from 'react-navigation';
import React,{Component} from 'react';
import {
Text,
View,
TouchableHighlight,
} from 'react-native';
// ==============
// Profile Screen
// ==============
class ProfileScreen extends Component {
static navigationOptions = {
title: 'Profile',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Profile Page</Text>
<TouchableHighlight onPress={() => this.onEditProfile()}><Text>Next</Text></TouchableHighlight>
</View>
);
}
onEditProfile() {
const { navigate } = this.props.navigation;
navigate('Detail');
}
}
// ==============
// Detail Screen
// ==============
class DetailScreen extends Component {
static navigationOptions = {
title: 'Detail',
}
render() {
const { navigate } = this.props.navigation;
return (
<View>
<Text>Detail Page</Text>
</View>
);
}
}
// ==============
// Routing
// ==============
const ModelStack = StackNavigator({
Profile: { screen: ProfileScreen },
Detail: { screen: DetailScreen },
});
export default ModelStack;