laravel 中的高级过滤器

Question

就我而言，我正在根据机构名称、位置和课程搜索培训机构

我有 3 table

institutes Table

id   |   institute_name       |  phone_number
----------------------------------------------
 1   |     vepsun             |   85214542462
----------------------------------------------
 2   |     infocampus         |   52466475544

Locations table

id   | institute_id(fk) |    location_name        
------------------------------------------------
 1   |  1               |      Banglore
------------------------------------------------
 2   |  1               |       delhi

courses table

 id   | institute_id(fk) |    course_name        
------------------------------------------------
 1   |  1               |      php
------------------------------------------------
 2   |  1               |      delhi

我在 3 tables tables

之间建立了关系

学院模型：

 public function locations()
 {
     return $this->hasMany(Location::class);
 }
  public function courses()
 {
     return $this->hasMany(Course::class);
 }

课程模型：

 public function institute()
 {
     return $this->belongsTo(Institute::class);
 }

位置模型：

  public function institute()
  {
     return $this->belongsTo(Institute::class);
  }

所以我尝试了下面的代码

  public function filter(Request $request)
  {
       $institute = (new Institute)->newQuery();

       // Search for a user based on their institute.

       if ($request->has('institute_name')) {
       $institute->where('institute_name', $request->input('institute_name'));
       }

      // Search for a user based on their course_name.

      if ($request->has('course_name')) {
      $institute->whereHas('courses', function ($query) use ($request) {
      $query->where('courses.course_name', $request->input('course_name'));
      });
      }

      // Search for a user based on their course_name.           

      if ($request->has('location_name')) {
      $institute->whereHas('locations', function ($query) use ($request) {
      $query->where('locations.location_name', $request->input('location_name'));
      });
      }
      return response()->json($institute->get());
  }

从上面的代码我可以过滤数据，但它只显示如下机构 table 数据。

  [
      {
          "id": 2,
          "institute_name": "qspider",
          "institute_contact_number": "9903456789",
          "institute_email": "qspider@gmail.com",
          "status": "1",
      }
  ]

但我需要的是当我使用 course_name 或 instute_name 进行搜索时，我需要从机构 table、课程和位置 table 获取数据。有人可以帮忙吗？

Answer 1

渴望在您的 if 语句中加载关系。

  // Search for a user based on their course_name.
  if ($request->has('course_name')) {
      $institute->whereHas('courses', function ($query) use ($request) {
          $query->where('courses.course_name', $request->input('course_name'));
      })
      ->with('courses); // <<<<<< add this line
  }

  // Search for a user based on their course_name.           
  if ($request->has('location_name')) {
      $institute->whereHas('locations', function ($query) use ($request) {
          $query->where('locations.location_name', $request->input('location_name'));
      })
      ->with('locations'); // <<<<<<< add this line
  }

这也将获取相关课程和位置。

laravel 中的高级过滤器

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