Hibernate 或 HQL Select 另一个 SELECT 的结果

Question

有没有办法在以下查询中使用 HQL？

SELECT userId, pwd, pwdDate FROM (SELECT userId, AES_DECRYPT(pwd, 'key_str') as pwd, pwdDate FROM UserHistory order by pwdDate desc limit 5 ) AS A WHERE pwd = :pwd

以下有效。

SELECT * FROM UserHistory order by pwdDate desc limit 5

上面的sql在hibernate中可以是下面的

Criteria criteria = session.createCriteria(UserHistory.class); criteria.addOrder(Order.desc("pwdDate")); List<UserHistory> list = criteria.setMaxResults(5).list();

Answer 1

以下有效。关键是为本机 SQL.

创建SQL查询

String SQL = 
"SELECT A.* FROM \n" +
"(select * \n" +
" from user_history$ order by pwdDate desc limit 5 ) AS A \n" + 
"where pwd = AES_ENCRYPT(:pwd, 'key_str') \n";

Query query = session.createSQLQuery(SQL);
query.setParameter("pwd", psw);
List<UserHistory> list = query.list();

Hibernate 或 HQL Select 另一个 SELECT 的结果

Hibernate or HQL Select on the result of another SELECT

java

mysql

hibernate

hql