为什么在表单提交期间验证两个随机数不起作用
Why is validating two random numbers during submission in a form not working
我有以下代码隐藏:
Random rndNum;
int inFirstOne, inSecondOne;
protected void Page_Load(object sender, EventArgs e)
{
rndNum = new Random();
int inFirst = rndNum.Next(1, 51);
int inSecond = rndNum.Next(50, 101);
lblFirst.Text = inFirst.ToString();
inFirstOne = inFirst;
lblSecond.Text = inSecond.ToString();
inSecondOne = inSecond;
}
public void ValidateForm(object sender, EventArgs e)
{
string strNum = tbValidation.Text;
int inCalc = inFirstOne + inSecondOne;
if (inCalc.ToString() == strNum)
{
lblIsValid.Text = "Correct";
}
else
{
lblIsValid.Text = "Please enter the correct result";
lblIsValid.ForeColor = Color.DarkRed;
}
}
ASP.net代码:
...
<tr>
<td><h2>What is <asp:Label ID="lblFirst" Text="" CssClass="numGen" ClientIDMode="Static" runat="server" /> + <asp:Label ID="lblSecond" Text="" CssClass="numGen" ClientIDMode="Static" runat="server" />?</h2></td>
<td><asp:TextBox ID="tbValidation" ClientIDMode="Static" CssClass="tbTech" runat="server"></asp:TextBox> <asp:Label ID="lblIsValid" runat="server" /></td>
</tr>
<tr>
<td colspan="2" class="setRight">
<asp:Button ID="SubmitForm" ClientIDMode="Static" runat="server" Text="Submit" OnClick="ValidateForm" CssClass="btn" UseSubmitBehavior="false" />
</td>
</tr>
...
我总是看到 Please enter the correct result
消息。
我如何修改以确保在输入结果时它可以从代码隐藏中验证计算。
不清楚你是如何填写的 tbValidation
但在任何情况下除非你执行你的 page_load
逻辑只有当请求不是回发时,变量 inFirstOne
和 inSecondOne
将在单击按钮时被覆盖。
看来你需要这个
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostback)
{
// do this only if it's the first request
rndNum = new Random();
int inFirst = rndNum.Next(1, 51);
int inSecond = rndNum.Next(50, 101);
lblFirst.Text = inFirst.ToString();
inFirstOne = inFirst;
lblSecond.Text = inSecond.ToString();
inSecondOne = inSecond
}
}
int inCalc = Convert.ToInt32(lblFirst.Text) + Convert.ToInt32(lblSecond.Text);
有效。
我有以下代码隐藏:
Random rndNum;
int inFirstOne, inSecondOne;
protected void Page_Load(object sender, EventArgs e)
{
rndNum = new Random();
int inFirst = rndNum.Next(1, 51);
int inSecond = rndNum.Next(50, 101);
lblFirst.Text = inFirst.ToString();
inFirstOne = inFirst;
lblSecond.Text = inSecond.ToString();
inSecondOne = inSecond;
}
public void ValidateForm(object sender, EventArgs e)
{
string strNum = tbValidation.Text;
int inCalc = inFirstOne + inSecondOne;
if (inCalc.ToString() == strNum)
{
lblIsValid.Text = "Correct";
}
else
{
lblIsValid.Text = "Please enter the correct result";
lblIsValid.ForeColor = Color.DarkRed;
}
}
ASP.net代码:
...
<tr>
<td><h2>What is <asp:Label ID="lblFirst" Text="" CssClass="numGen" ClientIDMode="Static" runat="server" /> + <asp:Label ID="lblSecond" Text="" CssClass="numGen" ClientIDMode="Static" runat="server" />?</h2></td>
<td><asp:TextBox ID="tbValidation" ClientIDMode="Static" CssClass="tbTech" runat="server"></asp:TextBox> <asp:Label ID="lblIsValid" runat="server" /></td>
</tr>
<tr>
<td colspan="2" class="setRight">
<asp:Button ID="SubmitForm" ClientIDMode="Static" runat="server" Text="Submit" OnClick="ValidateForm" CssClass="btn" UseSubmitBehavior="false" />
</td>
</tr>
...
我总是看到 Please enter the correct result
消息。
我如何修改以确保在输入结果时它可以从代码隐藏中验证计算。
不清楚你是如何填写的 tbValidation
但在任何情况下除非你执行你的 page_load
逻辑只有当请求不是回发时,变量 inFirstOne
和 inSecondOne
将在单击按钮时被覆盖。
看来你需要这个
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostback)
{
// do this only if it's the first request
rndNum = new Random();
int inFirst = rndNum.Next(1, 51);
int inSecond = rndNum.Next(50, 101);
lblFirst.Text = inFirst.ToString();
inFirstOne = inFirst;
lblSecond.Text = inSecond.ToString();
inSecondOne = inSecond
}
}
int inCalc = Convert.ToInt32(lblFirst.Text) + Convert.ToInt32(lblSecond.Text);
有效。