在 laravel 中出现数组错误时调用成员函数 paginate()

Question

我想在 laravel 中创建分页，但出现错误。这是错误 "Call to a member function paginate() on array"

这是我的查询

$blog = DB::select("select blog_post.*,(select img_name from blog_image WHERE blog_image.bid=blog_post.bid limit 0,1) as img_name, 
(SELECT count(*) FROM likes WHERE likes.bid =blog_post.bid) AS likes,
(SELECT count(*) FROM comment WHERE comment.bid =blog_post.bid ) as comments ,
(SELECT count(*) FROM blog_share WHERE blog_share.bid =blog_post.bid ) as  share 
from blog_post WHERE status=1 AND is_draft=0 AND is_publish=1 AND is_delete=0")->paginate(2);

Answer 1

您首先需要使用 Laravel Eloquent 重写您的查询。例如：

$blog = DB::table('blog_post')->where([ 'status' => 1, 'is_draft' => 0, 'is_publish' => 1, 'is_delete' = 0 ])->paginate(2);

您不需要严格地将所有计数/内部查询放入一个查询中。您可以使用 Eloquent Relationships and Mutators 为您获取该信息。比如下面的Relationship来获取图片：

class BlogPost extends Model
{

  public function image()
  {
    return $this->hasOne('BlogImage');
  }

}

在 laravel 中出现数组错误时调用成员函数 paginate()

Call to a member function paginate() on array error in laravel

laravel-5

laravel-query-builder