python3.5射程麻烦

Question

位置：[['120', '40', 'x1'], ['200', '50', 'x2'], ['150', '15', 'x3'], ['240', '60', 'x4'], ['260', '45', 'x5'], ['225', '15', 'x6'], ['273', '20', 'x7'], ['221', '5', 'x8'], ['345', '20', 'x9' ]]

范围：[['100', '0', '60', '40', 'x1'], ['80', '10', '30', '5', 'x2'], ['120', '0', '25', '10', 'x3'], ['100', '10', '0', '40', 'x4'], ['70', '0', '10', '25', 'x5'], ['75', '10', '5', '10', 'x6' ], ['75', '0', '0', '0', 'x7'], ['0', '0', '0', '0', 'x8'], ['0', '0', '0', '0', 'x9']]

 for a in range(int(locations[1][0])+int(rangee[1][0]),int(locations[1][0])-int(rangee[1][1])):

   print("x")

我有一个包含 integers.But 的位置列表，当我执行此操作时它不会 work.Any 知道为什么？

Answer 1

调试（_ 这不是调试，那只是打印出来并查看它_）你的数据 - 你的数据是无止境的：

使用

locations = [['120', '40', 'x1'], ['200', '50', 'x2'], ['150', '15', 'x3'], ['240', '60', 'x4'], ['260', '45', 'x5'], ['225', '15', 'x6'], ['273', '20', 'x7'], ['221', '5', 'x8'], ['345', '20', 'x9']]

rangee = [['100', '0', '60', '40', 'x1'], ['80', '10', '30', '5', 'x2'], ['120', '0', '25', '10', 'x3'], ['100', '10', '0', '40', 'x4'], ['70', '0', '10', '25', 'x5'], ['75', '10', '5', '10', 'x6'], ['75', '0', '0', '0', 'x7'], ['0', '0', '0', '0', 'x8'], ['0', '0', '0', '0', 'x9']]


from_loc = locations[1][0]
from_ran = rangee[1][0]
to_loc = locations[1][0]
to_ran = rangee[1][1]

print ( "from " , from_loc, " + " , from_ran, "     to: ", to_loc, " - " , to_ran )

输出：

('from ', '200', ' + ', '80', '     to: ', '200', ' - ', '10')

测试：

print ( range(280,190))

输出：

[]

==> 空列表 - 对于下降范围，您需要为步骤添加 ,-1：

print ( range(280,190,-1))

输出：

[280, 279, 278, 277, 276, ... , 192, 191]

这取决于你的用例，你可能想做这样的事情：

one = 280
two = 190

print (range( min(one,two), max(one,two))) # will sort them correctly

输出：[190, ..., 279]

或

print(range(one,two, 1 if one < two else -1))

这将根据其值将正确的步进添加到您的范围。

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