Python xlwt 单元格覆盖

Question

我正在尝试将列表 "words" 解析为一列，但我遇到了单元格覆盖问题。

import xlwt

wb=xlwt.Workbook()
sh=wb.add_sheet('sheet1')
sh.write(0,0,'words')

words = ["amazing","awesome","great"]
cols=['A']

for num in range(1,4):
     row = sh.row(num)
     for index,col in enumerate(cols):
             value = words[index]+str(num)
             row.write(index,value)   
wb.save('example.xls')

Answer 1

使用 sh.write() 就像您对 header 行所做的那样。使用 enumerate() 提供行号，从 1 开始（参见 enumerate() 的第二个参数）：

import xlwt

wb=xlwt.Workbook()
sh=wb.add_sheet('sheet1')
sh.write(0,0,'words')

words = ["amazing", "awesome", "great"]

for row, word in enumerate(words, start=1):
    sh.write(row, 0, word)
#    sh.write(row, 0, '{}{}'.format(word, row))    # use this if you want the row number appended

wb.save('example.xls')