C#在Unity游戏引擎中开箱后的倒计时

Question

我需要在打开盒子时访问 PC 或 Android 系统时间并保存，然后从那个时间开始倒计时 5 分钟。 5 分钟后，重新启用按钮以打开盒子。我尝试了很多方法，但都进入了死胡同。

public class Test : MonoBehaviour
{
    public Button boxButton;
    long previousOpenedBox;

    private void Update()
    {
        if (!boxButton.IsInteractable())
        {
            long diff = (DateTime.Now.Ticks - previousOpenedBox);
            //start counting down the time to re-enable the button.
        }
    }

    public void BoxClicked()
    {
        long previousOpenedBox = DateTime.Now.Ticks;
        boxButton.interactable = false;
    }
}

Answer 1

我不知道你为什么在更新盒子时要实现你的打开逻辑，你应该把它们放在 BoxClicked 方法中。这个最小的示例展示了如何处理阻塞延迟，应该会为您指明正确的路径。

public class Test : MonoBehaviour
{
    private DateTime m_LastOpening;
    public Button m_BoxButton;

    public void BoxClicked()
    {
        DateTime now = DateTime.Now;

        // 5 minutes elapsed, you can open the box
        if ((now - m_LastOpening).TotalMinutes > 5)
        {
            m_LastOpening = now;
            m_BoxButton.interactable = false;
        }
        else // otherwise you have to wait
        {
            // ...
        }
    }
}

C#在Unity游戏引擎中开箱后的倒计时

C# countdown after opening box in the Unity game engine

c#

android

unity3d

visual-studio

unity5