用于单元测试的 Django 工厂:"Cannot assign "'1'": "User.group" 必须是 "Brand" 实例。"

Django factories for unit test: "Cannot assign "'1'": "User.group" must be a "Brand" instance."

当我 运行 我的 user_profile/model.py 单元测试时出现错误:"Cannot assign "'1'": "User.group" 必须是一个 "Brand" 实例。"

我认为这个错误是因为,在我的单元测试工厂 (factories.py) 中,我在创建一个UserFactory() 的实例。我觉得 group 应该映射到 Brand class/factory 但我不知道该怎么做..

这是我的 user_profile/model.py:

class Brand(models.Model):

    name = models.CharField(max_length=20)

    def __unicode__(self):
        return self.name


class User(AbstractBaseUser, PermissionsMixin):

    username = models.CharField(
        'username',
        max_length=50,
        unique=True,
        db_index=True
    )
    email = models.EmailField('email address', unique=True)
    group = models.ForeignKey(Brand, null=True, blank=True)
    is_active = models.BooleanField(default=True)
    is_admin = models.BooleanField(default=False)
    is_staff = models.BooleanField(default=False)
    is_approved = models.BooleanField(default=True)

在我的 user_profile/test/factories.py:

from user_profile.models import User, Brand

class UserFactory(factory.django.DjangoModelFactory):

    class Meta:

        model = User
        django_get_or_create = (
            'username',
            'email',
            'password',
            'is_approved',
            'is_active',
            'is_staff',
            'is_admin',
            'group'
        )


class BrandFactory(factory.django.DjangoModelFactory):

    class Meta:

        model = Brand
        django_get_or_create = ('name',)

BrandFactory(name='BRAND1')
BrandFactory(name='BRAND2')
BrandFactory(name='BRAND3')
BrandFactory(name='BRAND4')


UserFactory(
    username='myuser1@gmail.com',
    email='myuser1@gmail.com',
    password=12345,
    is_approved=True,
    is_active=True,
    is_staff=True,
    is_admin=True,
    group="1" <--- HOW DO I MAP THIS TO THE 'BRAND1' FACTORY/CLASS?!
)

UserFactory(
    username='myuser2@gmail.com',
    email='myuser2@gmail.com',
    password=12345,
    is_approved=True,
    is_active=True,
    is_staff=True,
    is_admin=True,
    group="2"  <--- HOW DO I MAP THIS TO THE 'BRAND2' FACTORY/CLASS?!
)

您必须分配 BrandFactory 的return 值给某物。例如

b1 = BrandFactory(name='BRAND1')
b2 = BrandFactory(name='BRAND2')

然后在构造函数中使用对模型实例的引用

UserFactory(
    username='myuser1@gmail.com',
    email='myuser1@gmail.com',
    password=12345,
    is_approved=True,
    is_active=True,
    is_staff=True,
    is_admin=True,
    group=b1
)

UserFactory(
    username='myuser2@gmail.com',
    email='myuser12@gmail.com',
    password=12345,
    is_approved=True,
    is_active=True,
    is_staff=True,
    is_admin=True,
    group=b2
)