preg_split 带方括号

Question

我有一个具有以下结构的日志文件：

输入:

$logLine = "[2017-12-23 19:15:59:634187] [INFO] User SIMDesign successfully logged in."

我想从中获取一个数组（使用 preg_split 或 preg_match_all），如下所示：

预期输出:

[
 0 => '[2017-12-23 19:15:59:634187]',
 1 => '[INFO]',
 2 => 'User SIMDesign successfully logged in.'
]

或者这个：

[
 0 => '2017-12-23 19:15:59:634187',
 1 => 'INFO',
 2 => 'User SIMDesign successfully logged in.'
]

尝试次数：

我已经尝试了几个小时来寻找正则表达式模式，但不幸的是我没有找到适合我的解决方案。

preg_split("/[][]/", $logLine);

[
    0   =>  '',                                         //this is empty
    1   =>  '2017-12-23 19:15:59:634187',
    2   =>  ' ',                                        //there is a space
    3   =>  'INFO',
    4   =>  ' User SIMDesign successfully logged in.',
]

输出还可以，但不完美。我不需要数组的空元素 ([0], [2])。我需要去掉字符串“User SIMDesign successfully logged in”之前的 space。

preg_split("/[][]\s\S/", $logLine);

[
    0   =>  '[2017-12-12 12:12:12:132123',
    1   =>  'INFO',
    2   =>  'ser SIMDesign successfully logged in.'     //The first character of the string was removed (why?)
]

提前致谢

Answer 1

首先，您需要第一组括号之间的信息，但由于这些是正则表达式的特殊字符，我们将它们转义：[(.*?)] -> \[(.*?)\]

$logLine = "[2017-12-23 19:15:59:634187] [INFO] User SIMDesign successfully logged in."
            ^--------------------------^

然后是第二个括号，同理：[(.*?)] -> \[(.*?)\]

$logLine = "[2017-12-23 19:15:59:634187] [INFO] User SIMDesign successfully logged in."
                                         ^----^

而'the rest till the end'是(.*)$

$logLine = "[2017-12-23 19:15:59:634187] [INFO] User SIMDesign successfully logged in."
                                                ^------------------------------------^

它们之间有空格（\s）：\[(.*?)\]\s\[(.*?)\]\s(.*)$，有一个neat little demo here

我更喜欢我在上面写的答案，但是 preg_split 页面还记录了一些可以与 preg_split() 一起传递的标志，其中之一如下。我不是粉丝的原因是你 'hiding' 问题而不是修复它。

PREG_SPLIT_NO_EMPTY
If this flag is set, only non-empty pieces will be returned by preg_split().

preg_split 带方括号

preg_split with square brackets

php

regex

pcre

preg-split