使用 javax.ws.rs 的 Twitter oauth2
Twitter oauth2 using javax.ws.rs
我有使用 javax.ws.rs
的 Twitter 请求
WebTarget target = new WebTargetBuilder(client, OAUTH_API_ENDPOINT).build();
Builder request = target
.request(MediaType.APPLICATION_JSON)
.header("Authorization", "Basic " + encodedCredentials)
.header("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8");
Response postResponse = request
.post(Entity.entity("grant_type=client_credentials", MediaType.TEXT_PLAIN));
System.out.println(postResponse.readEntity(String.class));
encodedCredentials 是我使用 base 64 编码的消费者机密和消费者密钥。
我想做的请求是:
POST /oauth2/token HTTP/1.1
Host: api.twitter.com
User-Agent: My Twitter App v1.0.23
Authorization: Basic eHZ6MWV2RlM0d0VFUFRHRUZQSEJvZzpMOHFxOVBaeVJn
NmllS0dFS2hab2xHQzB2SldMdzhpRUo4OERSZHlPZw==Content-Type: application/x-www- form-urlencoded;charset=UTF-8
Content-Length: 29
Accept-Encoding: gzip
grant_type=client_credentials
我一直收到 403 禁止访问:{"errors":[{"code":170,"message":"Missing required parameter: grant_type","label":"forbidden_missing_parameter"}]}
似乎 post 正文设置不正确,有人知道如何设置吗?
我在 PHP 中使用了相同的内容,我认为您错过了必需的参数,例如 oauth_signature
您可以尝试更改 POST 请求 body/entity 的内容类型,如下所示:
.post(Entity.entity("grant_type=client_credentials", MediaType.APPLICATION_FORM_URLENCODED)
因此,从具有消费者密钥和消费者秘密的 Twitter 获取不记名令牌的最终代码如下所示:
private static final String OAUTH_API_ENDPOINT = "https://api.twitter.com/oauth2/token";
private String consumerKey = "your consumer key";
private String consumerSecret = "your consumer secret";
// Constructs the request for requesting a bearer token and returns that
// token as a string
public String requestBearerToken() throws IOException, InterruptedException, ExecutionException {
String encodedCredentials = encodeCredentials();
Client client = ClientBuilder.newClient();
WebTarget target = new WebTargetBuilder(client, OAUTH_API_ENDPOINT).build();
Response postResponse = target
.request(MediaType.APPLICATION_JSON)
.header("Authorization", "Basic " + encodedCredentials + "Content-Type: application/x-www-form-urlencoded;charset=UTF-8")
.post(Entity.entity("grant_type=client_credentials", MediaType.APPLICATION_FORM_URLENCODED));
return postResponse.toString();
}
// Encodes the consumer key and secret to create the basic authorization key
public String encodeCredentials() {
try {
String encodedConsumerKey = URLEncoder.encode(consumerKey, "UTF-8");
String encodedConsumerSecret = URLEncoder.encode(consumerSecret,
"UTF-8");
String fullKey = encodedConsumerKey + ":" + encodedConsumerSecret;
byte[] encodedBytes = Base64.encodeBase64(fullKey.getBytes());
return new String(encodedBytes);
} catch (UnsupportedEncodingException e) {
return new String();
}
}
我有使用 javax.ws.rs
的 Twitter 请求 WebTarget target = new WebTargetBuilder(client, OAUTH_API_ENDPOINT).build();
Builder request = target
.request(MediaType.APPLICATION_JSON)
.header("Authorization", "Basic " + encodedCredentials)
.header("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8");
Response postResponse = request
.post(Entity.entity("grant_type=client_credentials", MediaType.TEXT_PLAIN));
System.out.println(postResponse.readEntity(String.class));
encodedCredentials 是我使用 base 64 编码的消费者机密和消费者密钥。
我想做的请求是:
POST /oauth2/token HTTP/1.1
Host: api.twitter.com
User-Agent: My Twitter App v1.0.23
Authorization: Basic eHZ6MWV2RlM0d0VFUFRHRUZQSEJvZzpMOHFxOVBaeVJn
NmllS0dFS2hab2xHQzB2SldMdzhpRUo4OERSZHlPZw==Content-Type: application/x-www- form-urlencoded;charset=UTF-8
Content-Length: 29
Accept-Encoding: gzip
grant_type=client_credentials
我一直收到 403 禁止访问:{"errors":[{"code":170,"message":"Missing required parameter: grant_type","label":"forbidden_missing_parameter"}]}
似乎 post 正文设置不正确,有人知道如何设置吗?
我在 PHP 中使用了相同的内容,我认为您错过了必需的参数,例如 oauth_signature
您可以尝试更改 POST 请求 body/entity 的内容类型,如下所示:
.post(Entity.entity("grant_type=client_credentials", MediaType.APPLICATION_FORM_URLENCODED)
因此,从具有消费者密钥和消费者秘密的 Twitter 获取不记名令牌的最终代码如下所示:
private static final String OAUTH_API_ENDPOINT = "https://api.twitter.com/oauth2/token";
private String consumerKey = "your consumer key";
private String consumerSecret = "your consumer secret";
// Constructs the request for requesting a bearer token and returns that
// token as a string
public String requestBearerToken() throws IOException, InterruptedException, ExecutionException {
String encodedCredentials = encodeCredentials();
Client client = ClientBuilder.newClient();
WebTarget target = new WebTargetBuilder(client, OAUTH_API_ENDPOINT).build();
Response postResponse = target
.request(MediaType.APPLICATION_JSON)
.header("Authorization", "Basic " + encodedCredentials + "Content-Type: application/x-www-form-urlencoded;charset=UTF-8")
.post(Entity.entity("grant_type=client_credentials", MediaType.APPLICATION_FORM_URLENCODED));
return postResponse.toString();
}
// Encodes the consumer key and secret to create the basic authorization key
public String encodeCredentials() {
try {
String encodedConsumerKey = URLEncoder.encode(consumerKey, "UTF-8");
String encodedConsumerSecret = URLEncoder.encode(consumerSecret,
"UTF-8");
String fullKey = encodedConsumerKey + ":" + encodedConsumerSecret;
byte[] encodedBytes = Base64.encodeBase64(fullKey.getBytes());
return new String(encodedBytes);
} catch (UnsupportedEncodingException e) {
return new String();
}
}