将持续时间格式从 float 转换为 Month:Days:Hours:Minutes:Seconds in python 3.x

Question

我有一个浮点数 12634.0 作为持续时间结果。我想把它转换成这种格式： Months:Days:Hours:Minutes:Seconds (00:00:03:30:34)

我怎样才能做到这一点？谢谢

Answer 1

你可以试试

import datetime
print (str(datetime.timedelta(seconds=12634))

Answer 2

另一种解决方案，如果您需要其他信息，例如周数：

import datetime

def time_in_sec(time_sec):

    delta = datetime.timedelta(seconds=time_sec)
    delta_str = str(delta)[-8:]
    hours, minutes, seconds = [int(val) for val in delta_str.split(":", 3)]
    weeks = delta.days // 7
    days = delta.days % 7
    return "{}:{}:{}:{}:{}".format(weeks, days, hours, minutes, seconds)


def time_in_sec2(seconds):

    WEEK = 60 * 60 * 24 * 7
    DAY = 60 * 60 * 24
    HOUR = 60 * 60
    MINUTE = 60

    weeks = seconds // WEEK
    seconds = seconds % WEEK
    days = seconds // DAY
    seconds = seconds % DAY
    hours = seconds // HOUR
    seconds = seconds % HOUR
    minutes = seconds // MINUTE
    seconds = seconds % MINUTE
    return "{}:{}:{}:{}:{}".format(weeks, days, hours, minutes, seconds)


def main():
    print(time_in_sec(12634.0))
    print(time_in_sec2(12634.0))

结果是：

0:0:3:30:34
0.0:0.0:3.0:30.0:34.0

如果您不想要周等信息，可以简单地删除它

如果您不想要像

这样的依赖项，您可以采用解决方案 2 (time_in_sec2)

import datetime

将持续时间格式从 float 转换为 Month:Days:Hours:Minutes:Seconds in python 3.x

Convert duration format from float to Month:Days:Hours:Minutes:Seconds in python 3.x

python

duration

python-3.x