获取 Google 日历事件的 eventID

Get eventID for Google Calendar Event

我想借助 google 脚本从特定事件中获取 eventID。我目前正在使用这个变量:

function export_gcal_to_gsheet(){

// Reference Websites:
// https://developers.google.com/apps-script/reference/calendar/calendar
// https://developers.google.com/apps-script/reference/calendar/calendar-event
//

var mycal = "info@neugier.schule";
var cal = CalendarApp.getCalendarById(mycal);
var today = new Date()
var thisweek = new Date (today.getTime())
var oneWeekfromNow = new Date(today.getTime() + (7*3600000*24));

//
var events = cal.getEvents(thisweek, oneWeekfromNow, {search: 'stammtisch'});

var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Termine");
// Uncomment this next line if you want to always clear the spreadsheet content before running - Note people could have added extra columns on the data though that would be lost
//sheet.clearContents();  

// Create a header record on the current spreadsheet in cells A1:N1 - Match the number of entries in the "header=" to the last parameter
// of the getRange entry below
var header = [["Event Title", "Event Start", "Thema", "LinkZoom", "EventID"]]
var range = sheet.getRange(1,1,1,5);
range.setValues(header);


// Loop through all calendar events found and write them out starting on calulated ROW 2 (i+2)
for (var i=0;i<events.length;i++) {
var row=i+2;
var myformula_placeholder = '';
// Matching the "header=" entry above, this is the detailed row entry "details=", and must match the number of entries of the GetRange entry below
// NOTE: I've had problems with the getVisibility for some older events not having a value, so I've had do add in some NULL text to make sure it does not error
  var details=[[events[i].getTitle(), Utilities.formatDate(events[i].getStartTime(),'Europe/Berlin', 'dd.MM.yyyy,\' um\' HH:mm\'Uhr\''), events[i].getDescription(), events[i].getLocation(), events[i].getId()]];

var range=sheet.getRange(row,1,1,5);
range.setValues(details);

}
}

但 getId 似乎与事件 ID 不同,因为当我将 ID 插入此 link 时:https://www.google.com/calendar/event?eid={event-id}&ctz={timezone}

我收到一个错误。此外,当我手动共享我的事件时,我看到的 ID 与我从脚本中获得的 ID 不同。

希望有人能帮帮我。

我了解到您希望 event-id 使用 https://www.google.com/calendar/event?eid={event-id}&ctz={timezone}。我的理解正确吗?如果我的理解是正确的,这个修改怎么样?

修改点:

  • 为了检索 https://www.google.com/calendar/event?eid={event-id}&ctz={timezone}event-id,您可以使用日历 API 的 Calendar.Events.list() 检索它。

准备使用此修改后的示例脚本:

当您使用此修改后的脚本时,请在高级 Google 服务和 API 控制台启用日历 API。

在高级 Google 服务中启用日历 API v3

  • 在脚本编辑器上
    • 资源 -> 高级 Google 服务
    • 打开日历 API v3

Enable Calendar API at API console

  • 在脚本编辑器上
    • 资源 -> 云平台项目
    • 查看API控制台
    • 在开始时,单击启用 APIs 并获取密钥等凭据。
    • 在左侧,单击“库”。
    • 在搜索 API 和服务时,输入 "Calendar"。然后单击日历 API。
    • 单击“启用”按钮。
    • 如果API已经启用,请不要关闭。
    • 当你运行这个脚本时,如果发生错误,你可能需要等待几分钟,直到API被启用。

修改脚本:

function export_gcal_to_gsheet(){
  var mycal = "info@neugier.schule";
  var cal = CalendarApp.getCalendarById(mycal);
  var today = new Date()
  var thisweek = new Date (today.getTime())
  var oneWeekfromNow = new Date(today.getTime() + (7*3600000*24));
  var events = cal.getEvents(thisweek, oneWeekfromNow, {search: 'stammtisch'});
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Termine");
  var header = [["Event Title", "Event Start", "Thema", "LinkZoom", "EventID"]]
  var range = sheet.getRange(1,1,1,5);
  range.setValues(header);

  // Added
  var items = Calendar.Events.list(mycal, {
    timeMin: thisweek.toISOString(),
    timeMax: oneWeekfromNow.toISOString(),
    q: 'stammtisch'
  }).items;

  for (var i=0;i<events.length;i++) {
    var row=i+2;
    var myformula_placeholder = '';
    var details=[[events[i].getTitle(), Utilities.formatDate(events[i].getStartTime(),'Europe/Berlin', 'dd.MM.yyyy,\' um\' HH:mm\'Uhr\''), events[i].getDescription(), events[i].getLocation(), items[i].htmlLink.split("=")[1]]]; // Modified
    var range=sheet.getRange(row,1,1,5);
    range.setValues(details);
  }
}

注:

  • 此修改后的脚本从 Calendar.Events.list() 中检索 htmlLink。 link 是 https://www.google.com/calendar/event?eid={event-id}。现在我从 link 中检索了 event-id 以使用 items[i].htmlLink.split("=")[1] 匹配您的脚本。如果您想要link,请修改为items[i].htmlLink

参考资料:

如果我误解了你的问题,我很抱歉。