属性的级别值错误，无法为 java.util.logging.FileHandler 设置级别

Question

这是一项学校作业：我必须构建一个自定义记录器 class 能够从我项目中的任何地方进行记录。

我只能用java.util.logger。我在我的项目中使用位于 /conf 文件夹中的属性文件。

我收到这个错误：

Bad level value for property: java.util.logging.FileHandler.level

Can't set level for java.util.logging.FileHandler

我想这就是为什么我的 debug() 方法不能在我的文件中打印“ddd”，也是为什么我不能用我设置的这个字符串格式化文件：“[%1$tc] - [%2 $s] [%4$s] [%5$s] %n".

我无法理解我可能在 conf 文件或代码中犯了什么错误：导入是正确的，我没有 errors/warnings 代码。

我知道我永远不应该使用绝对路径，但我不认为这是我的问题，路径将在我解决此问题后修复。

我的 try.log 在我的 /test 文件夹中的输出：

03-Jan-2018 14:01:03 logger.classLogger warning

WARNING: attention please

please 03-Jan-2018 14:01:03 logger.classLogger error

SEVERE: error

03-Jan-2018 14:01:03 logger.classLogger info

INFO: info

这是我的 .properties 文件：

.level=ALL
handlers = java.util.logging.FileHandler 
java.util.logging.FileHandler.level = FINE 
java.util.logging.FileHandler.append = true 
java.util.logging.FileHandler.limit = 1000000 
java.util.logging.FileHandler.count = 100 
java.util.logging.FileHandler.pattern =  %t/Log%u%g.log
java.util.logging.SimpleFormatter.format = "[%1$tc] - [%2$s] [%4$s] [%5$s] %n"
java.util.logging.FileHandler.formatter =  java.util.logging.SimpleFormatter

这是我的 class:

  public class classLogger {

  Logger logger;
  FileHandler fh;
  SimpleFormatter sf;

  public classLogger(String classname){

    this.logger = Logger.getLogger(classname);
    logger.setLevel(Level.ALL);

    try {
      String path = "D:\myprojects\logger\conf\logging.properties";
      FileInputStream configFile = new FileInputStream(path); 
      LogManager.getLogManager().readConfiguration(configFile);
    }
    catch (IOException ex)
    {
    }
 
    try {
      String directory = "C:\Documents and Settings\E520user\Desktop\test"; 
      String filename = "\try.log";
      this.fh = new FileHandler(directory+filename);
    }
    catch (IOException ex1) {
      
    }

    this.sf = new SimpleFormatter();

    //set formatter
    fh.setFormatter(sf);

    //add handler
    logger.addHandler(fh);

  }

  public void error(String msg){
    logger.severe(msg);
  }

  public void warning(String msg){
    logger.warning(msg);
  }

  public void info(String msg){
    logger.info(msg);
  }

  public void debug(String msg){
    logger.fine(msg);
  }
  public static void main(String[] args) {

    IRSLogger log = new classLogger(classLogger.class.getName());
    log.warning("attention please");
    log.error("error");
    log.debug("dddd");
    log.info("info");

  }
}

Answer 1

在我的 Mac 上试了一下，效果很好

$ cat try.log 
"[Wed Jan 03 14:35:22 GMT 2018] - [classLogger warning] [WARNING] [attention please] 
""[Wed Jan 03 14:35:22 GMT 2018] - [classLogger error] [SEVERE] [error] 
""[Wed Jan 03 14:35:22 GMT 2018] - [classLogger debug] [FINE] [dddd] 
""[Wed Jan 03 14:35:22 GMT 2018] - [classLogger info] [INFO] [info]

不过我也收到这条消息：Can't set level for java.util.logging.FileHandler

您可以尝试从您的属性文件中删除 java.util.logging.FileHandler.level = FINE 吗？

提示

您应该删除此行中的 "：java.util.logging.SimpleFormatter.format = "[%1$tc] - [%2$s] [%4$s] [%5$s] %n"

编辑：这适用于我的电脑

import java.io.FileInputStream;
import java.io.IOException;
import java.util.logging.*;

public class ClassLogger {

  private Logger logger;
  private FileHandler fh;

  public ClassLogger(String classname){

    this.logger = Logger.getLogger(classname);

    try {
      String path = "/Users/myUser/Workspace/Whosebug/test/src/main/java/logging.properties";
      FileInputStream configFile = new FileInputStream(path);
      LogManager.getLogManager().readConfiguration(configFile);
    } catch (IOException ex) {
      ex.printStackTrace();
    }

    try {
      String directory = "/Users/myUser/Workspace/Whosebug/test/src/main/java/";
      String filename = "try.log";
      this.fh = new FileHandler(directory+filename);
    } catch (IOException ex1) {
      ex1.printStackTrace();
    }

    //add handler
    logger.addHandler(fh);
  }

  public void error(String msg) { logger.severe(msg);}
  public void warning(String msg) { logger.warning(msg); }
  public void info(String msg) { logger.info(msg); }
  public void debug(String msg) { logger.fine(msg); }

  public static void main(String[] args) {
    ClassLogger log = new ClassLogger(ClassLogger.class.getName());
    log.warning("attention please");
    log.error("error");
    log.debug("dddd");
    log.info("info");
  }
}

logging.properties

.level=ALL
handlers = java.util.logging.FileHandler
java.util.logging.FileHandler.append = true
java.util.logging.FileHandler.limit = 1000000
java.util.logging.FileHandler.count = 100
java.util.logging.FileHandler.pattern =  %t/Log%u%g.log
java.util.logging.SimpleFormatter.format = [%1$tc] - [%2$s] [%4$s] [%5$s] %n
java.util.logging.FileHandler.formatter =  java.util.logging.SimpleFormatter

在try.log

输出

[Wed Jan 03 15:27:55 GMT 2018] - [ClassLogger warning] [WARNING] [attention please] 
[Wed Jan 03 15:27:55 GMT 2018] - [ClassLogger error] [SEVERE] [error] 
[Wed Jan 03 15:27:55 GMT 2018] - [ClassLogger debug] [FINE] [dddd] 
[Wed Jan 03 15:27:55 GMT 2018] - [ClassLogger info] [INFO] [info]

属性 的级别值错误，无法为 java.util.logging.FileHandler 设置级别

Bad level value for property and can't set level for java.util.logging.FileHandler

java

logging

properties

java.util.logging

属性的级别值错误，无法为 java.util.logging.FileHandler 设置级别