访问@IBAction 的属性 of ViewController 并将其传递给 SecondViewController

Question

如何从 ViewController 的 IBAction 方法访问 points 属性并传递它至 scoreLabel 共 SecondViewController?

import UIKit

class ViewController: UIViewController {
    var points: Int = 0

    @IBAction func action(sender: UIButton) {
        points += 1
    }
}



class SecondViewController: UIViewController {
    @IBOutlet weak var scoreLabel: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()
    }
}

Answer 1

注意：这是假设您要从 ViewController.

转到 SecondViewController

在 SecondViewController 中，声明一个名为 score 或类似名称的变量：

var score: Int = 0

在 ViewController 中，像这样实现 prepareForSegue 方法：

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "YourSegueIdentifierForSecondViewController" {
        if let secondViewController = segue.destination as? SecondViewController {
            secondViewController.score = points
        }
    }
}

然后在SecondViewController的viewDidLoad中，你可以为你的标签设置分数：

scoreLabel.text = String(score)

访问@IBAction 的属性 of ViewController 并将其传递给 SecondViewController

Accessing @IBAction's property of ViewController and pass it to SecondViewController

properties

uiviewcontroller

swift4

ios11

访问@IBAction 的 属性 of ViewController 并将其传递给 SecondViewController

Accessing @IBAction's property of ViewController and pass it to SecondViewController

properties

uiviewcontroller

swift4

ios11

访问@IBAction 的属性 of ViewController 并将其传递给 SecondViewController