Swift 组合谓词 LogicalType AND OR

Swift combining predicates LogicalType AND OR

如何在 Swift 谓词中组合混合 AND OR 条件。我有以下查询

 Select * from tblTemp where dept == 1 && (subdept == 11 || subdept == 12)

我可以用相同的运算符写两个谓词,但不知道如何组合它们

    let deptPredicate = NSPredicate(format: "dept == %@", 1)
    let subdeptPredicate1 = NSPredicate(format: "subdept = %@", 11)
    let subdeptPredicate2 = NSPredicate(format: "subdept = %@", 12)
    let andPredicate = NSCompoundPredicate(type: NSCompoundPredicate.LogicalType.and, subpredicates: [deptPredicate, subdeptPredicate1])

NSCompoundPredicateNSPredicate的子类,意思是 结果是 NSCompoundPredicate(type:subpredicates:) 可用于另一种化合物 谓词。

但是请注意,%@ 格式占位符需要一个 NSObject 实例:

let deptPredicate = NSPredicate(format: "dept == %@", 1 as NSNumber)
let subdeptPredicate1 = NSPredicate(format: "subdept = %@", 11 as NSNumber)
let subdeptPredicate2 = NSPredicate(format: "subdept = %@", 12 as NSNumber)

let orPredicate = NSCompoundPredicate(type: .or,
                                      subpredicates: [subdeptPredicate1, subdeptPredicate2])

let andPredicate = NSCompoundPredicate(type: .and,
                                       subpredicates: [deptPredicate, orPredicate])

或者,对整数使用 %ld 格式:

let deptPredicate = NSPredicate(format: "dept == %ld", 1)
// ... etc.

还有方便的初始化器:

let orPredicate = NSCompoundPredicate(orPredicateWithSubpredicates:
    [subdeptPredicate1, subdeptPredicate2])

let andPredicate = NSCompoundPredicate(andPredicateWithSubpredicates:
    [deptPredicate, orPredicate])

复合谓词对于组合一组动态的 运行时的条件。另一方面,如果只有 values 改变 那么您可以在谓词中简单地使用 "AND" 和 "OR" 格式字符串:

NSPredicate(format: "dept == %ld AND (subdept = %ld OR subdept = %ld)", 1, 11, 12)

最后请注意,您可以将 #keyPath 指令与 %K占位符,让编译器填入正确的属性 名称(从而减少打字错误的机会):

let deptPredicate = NSPredicate(format: "%K == %ld", #keyPath(MyEntity.dept), 1)