有条件的多语言 laravel 播种机

Question

假设我有一个 table，其中包含一组多种语言的数据和一个引用语言 table 上的 code 的外键 lang_code。

现在我必须根据 lang_code（en，es）播种数据 table。如何根据分配的外键值使条件播种机播种，即如果 lang_code 是 en 那么用英语播种等等？

这是我在 dataTableSeeder 上的内容

public function run(Faker $faker)
{
    $fakerEs = Faker\Factory::create('es_ES');
    $instructionIDs = DB::table('oes_instructions')->pluck('id')->toArray();;
    $languageIDs = DB::table('oes_languages')->pluck('code')->toArray();;

    foreach (range(1,4) as $index) {
        DB::table('oes_exam_instructions_data')->insert([
        'instruction_id' => $faker->randomElement($instructionIDs),
        'locale' => $faker->randomElement($languageIDs), 
        'content' => $faker->paragraphs(10, $asText = true),   
        //Here ho do i make this based on $languageIDs => $faker->paragraphs(10, $asText = true) 
        'created_at' => Carbon::now()->format('Y-m-d H:i:s'),
        'updated_at' => Carbon::now()->format('Y-m-d H:i:s')
        ]);
    }
}

Answer 1

好的很简单，但我认为使用 Model Factory 会更容易。

$fakerEs = Faker\Factory::create('es_ES');
    $instructionIDs = DB::table('oes_instructions')->pluck('id')->toArray();
    $languageIDs = DB::table('oes_languages')->pluck('code')->toArray();

    foreach ($instructionIDs as $instructionID) {
        foreach ($languageIDs as $languageID) {
            $data = ($languageID == 'en') ? $faker->paragraphs(6, $asText = true) : $fakerEs->paragraphs(6, $asText = true);
            DB::table('oes_instructions_data')->insert([
            'instruction_id' => $instructionID,
            'locale' => $languageID,
            'content' => $data,
            'created_at' => Carbon::now()->format('Y-m-d H:i:s'),
            'updated_at' => Carbon::now()->format('Y-m-d H:i:s')
            ]);
        }
    }

有条件的多语言 laravel 播种机

conditional multi-lingual laravel seeder

php

mysql

multilingual

laravel-5