Jackson:UnrecognisedPropertyException

Question

我有以下 classes:

LocationCustomDataItem.java

public class LocationCustomDataItem {

private String attributeNumber;
private String attributeLabel;
private String attributeValue;

public LocationCustomDataItem() {

}

public LocationCustomDataItem(final String attributeNumber, final String attributeLabel, final String attributeValue) {
    this.attributeNumber = attributeNumber;
    this.attributeLabel = attributeLabel;
    this.attributeValue = attributeValue;
}
/**
 * @return the attributeNumber
 */
public String getAttributeNumber() {
    return attributeNumber;
}
/**
 * @param attributeNumber the attributeNumber to set
 */
public void setAttributeNumber(String attributeNumber) {
    this.attributeNumber = attributeNumber;
}
/**
 * @return the attributeLabel
 */
public String getAttributeLabel() {
    return attributeLabel;
}
/**
 * @param attributeLabel the attributeLabel to set
 */
public void setAttributeLabel(String attributeLabel) {
    this.attributeLabel = attributeLabel;
}
/**
 * @return the attributeValue
 */
public String getAttributeValue() {
    return attributeValue;
}
/**
 * @param attributeValue the attributeValue to set
 */
public void setAttributeValue(String attributeValue) {
    this.attributeValue = attributeValue;
}

@Override
public int hashCode() {
    return HashCodeBuilder.reflectionHashCode(this, false);
}

@Override
public boolean equals(Object obj) {
    return EqualsBuilder.reflectionEquals(this, obj);
}

@Override
public String toString() {
    return ToStringBuilder.reflectionToString(this, ToStringStyle.SHORT_PREFIX_STYLE, false);
}

LocationCustomDataAttributes.java

public class LocationCustomDataAttributes {

private final List<LocationCustomDataItem> locationCustomDataItems;

public LocationCustomDataAttributes() {
    this.locationCustomDataItems = new ArrayList<>();
}

public LocationCustomDataAttributes(final List<LocationCustomDataItem> locationCustomDataItems) {
    this.locationCustomDataItems = locationCustomDataItems;
}

/**
 * @return unmodifiable locationCustomDataItems list
 */
public List<LocationCustomDataItem> getLocationCustomDataItems() {
    return Collections.unmodifiableList(this.locationCustomDataItems);
}

/**
 * Adds LocationCustoDataItem to internal collection
 * 
 * @param item LocationCustomDataItem to add to item list
 */
public void addItem(final LocationCustomDataItem item) {
    this.locationCustomDataItems.add(item);
}


@Override
public int hashCode() {
    return HashCodeBuilder.reflectionHashCode(this, false);
}

@Override
public boolean equals(Object obj) {
    return EqualsBuilder.reflectionEquals(this, obj);
}

@Override
public String toString() {
    return ToStringBuilder.reflectionToString(this, ToStringStyle.SHORT_PREFIX_STYLE, false);
}

和这个测试 json:

{
   "locationCustomDataAttributes" : {
      "locationCustomDataItems" : [ {
         "attributeLabel" : "testLabel1",
         "attributeNumber" : "testNumber1",
         "attributeValue" : "testLabel1"
      }, {
         "attributeLabel" : "testLabel2",
         "attributeNumber" : "testNumber2",
         "attributeValue" : "testLabel2"
      } ]
   }
}

我正在尝试使用 ObjectMapper 将 json 转换为对象，但它在 "locationCustomDataAttributes":

周围引发了无法识别的 PropertyException

MapperTest.java

@Test
public void test() throws JsonParseException, JsonMappingException, IOException {
    ObjectMapper om =new ObjectMapper();

    LocationCustomDataAttributes actual = om.readValue(json, LocationCustomDataAttributes.class);

    LocationCustomDataAttributes expected = new LocationCustomDataAttributes();
    expected.addItem(new LocationCustomDataItem("testNumber1", "testLabel1", "testValue1"));
    expected.addItem(new LocationCustomDataItem("testNumber2", "testLabel2", "testValue2"));

    assertThat(actual).isEqualTo(expected);
}

错误信息：

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "locationCustomDataAttributes" (class com.lmig.ci.fnol.transformer.domain.LocationCustomDataAttributes), not marked as ignorable (one known property: "locationCustomDataItems"])
 at [Source: {"locationCustomDataAttributes" : {"locationCustomDataItems" : [ {"attributeLabel" : "testLabel1","attributeNumber" : "testNumber1","attributeValue" : "testLabel1"},{"attributeLabel" : "testLabel2","attributeNumber" : "testNumber2","attributeValue" : "testLabel2"}]}}; line: 1, column: 36] (through reference chain: com.lmig.ci.fnol.transformer.domain.LocationCustomDataAttributes["locationCustomDataAttributes"])
at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:62)
at com.fasterxml.jackson.databind.DeserializationContext.handleUnknownProperty(DeserializationContext.java:833)
at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1096)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1467)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1445)

//等...`

我没有直接与 Jackson 合作的大量经验，所以我还没有注释 class 本身，但是从以前的努力（例如 Spring 控制器）转换无需在 class 上添加注释即可自动发生。在这种情况下，情况似乎并非如此，我从 class 中遗漏了什么，或者当前的 class 结构是否出于某种原因不适合 Jackson 自动转换？

Answer 1

om.readValue(json, LocationCustomDataAttributes.class)

此行要求解析 JSON 文档中的 LocationCustomDataAttributes 对象。但是 JSON 实际上包含一个包装器对象，带有属性可以解析为 LocationCustomDataAttributes 对象。解决方案：

为包装对象创建一个 reader。例如

ObjectReader reader = om
    .readerFor(LocationCustomDataAttributes.class)
    .withRootName("locationCustomDataAttributes");
LocationCustomDataAttributes actual = reader.readValue(json);

定义包装器class

class AttributesWrapper {
    private LocationCustomDataAttributes locationCustomDataAttributes;
    // add getters, setters, constructors etc
}

然后解析它：

LocationCustomDataAttributes actual = om
    .readValue(json, AttributesWrapper.class)
    .getLocationCustomDataAttributes();

Jackson:UnrecognisedPropertyException

Jackson:UnrecognisedPropertyException

java

json

jackson

jackson-databind