为什么我在维基百科 api 上收到错误消息?
Why do I get error message on wikipedia api?
有人能告诉我这段代码有什么问题吗?
$.ajax({
"url":"https://en.wikipedia.org/w/api.php?",
"dataType": "jsonp",
"action": "opensearch",
"format": "json",
"search": "new york",
"namespace": "0",
"limit": "3",
"formatversion": "1",
success: function(response){
console.log(response);
}
});
为什么我会收到以下错误消息?
拒绝执行来自“https://en.wikipedia.org/w/api.php?&callback=jQuery111105448874468459555_1518288921946&_=1518288921947”的脚本,因为它的 MIME 类型 ('text/html') 不可执行,并且启用了严格的 MIME 类型检查。
谢谢。
以下不是 ajax 参数(而是 api 参数):
"action": "opensearch",
"format": "json",
"search": "new york",
"namespace": "0",
"limit": "3",
"formatversion": "1",
您可以将这些值作为查询字符串传递,将您的 url 更改为:
"url":"https://en.wikipedia.org/w/api.php?",
至:
"url":"https://en.wikipedia.org/w/api.php?"+ $.param(apiParams),
其中 api 参数为:
var apiParams = {action: 'opensearch', search: 'new york', limit: 3, namespace: 0, formatversion: 1, format: 'json'};
或者您可以使用如下数据参数:
data: apiParams,
片段:
var apiParams = {action: 'opensearch', search: 'new york', limit: 3, namespace: 0, formatversion: 1, format: 'json'};
$.ajax({
"url":"https://en.wikipedia.org/w/api.php?" + $.param(apiParams),
"dataType": "jsonp",
//data: apiParams,
success: function(response){
console.log(JSON.stringify(response));
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
有人能告诉我这段代码有什么问题吗?
$.ajax({
"url":"https://en.wikipedia.org/w/api.php?",
"dataType": "jsonp",
"action": "opensearch",
"format": "json",
"search": "new york",
"namespace": "0",
"limit": "3",
"formatversion": "1",
success: function(response){
console.log(response);
}
});
为什么我会收到以下错误消息?
拒绝执行来自“https://en.wikipedia.org/w/api.php?&callback=jQuery111105448874468459555_1518288921946&_=1518288921947”的脚本,因为它的 MIME 类型 ('text/html') 不可执行,并且启用了严格的 MIME 类型检查。
谢谢。
以下不是 ajax 参数(而是 api 参数):
"action": "opensearch",
"format": "json",
"search": "new york",
"namespace": "0",
"limit": "3",
"formatversion": "1",
您可以将这些值作为查询字符串传递,将您的 url 更改为:
"url":"https://en.wikipedia.org/w/api.php?",
至:
"url":"https://en.wikipedia.org/w/api.php?"+ $.param(apiParams),
其中 api 参数为:
var apiParams = {action: 'opensearch', search: 'new york', limit: 3, namespace: 0, formatversion: 1, format: 'json'};
或者您可以使用如下数据参数:
data: apiParams,
片段:
var apiParams = {action: 'opensearch', search: 'new york', limit: 3, namespace: 0, formatversion: 1, format: 'json'};
$.ajax({
"url":"https://en.wikipedia.org/w/api.php?" + $.param(apiParams),
"dataType": "jsonp",
//data: apiParams,
success: function(response){
console.log(JSON.stringify(response));
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>