在下面用 C++ 简化我的代码
simplify my code in C++ below
我想创建一个能够计算表面积、体积和周长的程序。对于您的额外信息,我正在研究函数,我刚刚学习 C++ 大约一周。
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
int getPostP(string msgP)
{
int Ppost= 0.000;
do
{
cout << msgP << endl;
cin >> Ppost;
return Ppost;
} while(Ppost<= 0);
}
int getPostL(string msgL)
{
int Lpost= 0.000;
do
{
cout << msgL << endl;
cin >> Lpost;
return Lpost;
} while(Lpost<= 0);
}
int getPostT(string msgT)
{
int Tpost = 0.000;
do
{
cout << msgT << endl;
cin >> Tpost;
return Tpost;
} while(Tpost <= 0);
}
int surfaceArea(int Psur, int Lsur, int Tsur)
{
return (2*Psur*Lsur)+(2*Psur*Tsur)+(2*Lsur*Tsur);
}
int volume(int Pvol, int Lvol, int Tvol)
{
return (Pvol*Lvol*Tvol);
}
float circumference(int Pcir, int Lcir, int Tcir)
{
return 4*(Pcir+Lcir+Tcir);
}
int main()
{
int P = getPostP("enter the P of your block");
int L = getPostL("enter the L of your block");
int T = getPostT("enter the T of your block");
float surfAreaBlock = surfaceArea(P, L, T);
float volBlock = volume(P, L, T);
float cirBlock = circumference(P, L, T);
cout << "block which have P = " << P << " and L = " << L << " and T = "<< T << " have surface area = " <<
surfAreaBlock << " and volume = " << volBlock << " and cirBlock = " << cirBlock;
return 0;
}
也许你们中有人想重写并添加一些注释,哪些部分可以简化,这样我就可以更容易理解。
首先,您似乎应该将所有整数输入 double
而不是 int
,因为预计您的输入不一定是精确的整数(大概)。您还可以删除所有用于输入参数的重复函数。将其更改为单个函数并为每个变量调用该函数。
double getInput(const std::string& prompt)
{
double input(0.0);
do
{
std::cout << prompt << "\n-> " << std::flush;
// forces input to be a double type
while (!(std::cin >> input))
{
std::cout << "\n-> " << std::flush;
std::cin.clear();
std::cin.ignore(256, '\n'); ///< could use streamsize::max here
}
} while (input <= 0.0); ///< make sure it's positive
return input;
}
我想创建一个能够计算表面积、体积和周长的程序。对于您的额外信息,我正在研究函数,我刚刚学习 C++ 大约一周。
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
int getPostP(string msgP)
{
int Ppost= 0.000;
do
{
cout << msgP << endl;
cin >> Ppost;
return Ppost;
} while(Ppost<= 0);
}
int getPostL(string msgL)
{
int Lpost= 0.000;
do
{
cout << msgL << endl;
cin >> Lpost;
return Lpost;
} while(Lpost<= 0);
}
int getPostT(string msgT)
{
int Tpost = 0.000;
do
{
cout << msgT << endl;
cin >> Tpost;
return Tpost;
} while(Tpost <= 0);
}
int surfaceArea(int Psur, int Lsur, int Tsur)
{
return (2*Psur*Lsur)+(2*Psur*Tsur)+(2*Lsur*Tsur);
}
int volume(int Pvol, int Lvol, int Tvol)
{
return (Pvol*Lvol*Tvol);
}
float circumference(int Pcir, int Lcir, int Tcir)
{
return 4*(Pcir+Lcir+Tcir);
}
int main()
{
int P = getPostP("enter the P of your block");
int L = getPostL("enter the L of your block");
int T = getPostT("enter the T of your block");
float surfAreaBlock = surfaceArea(P, L, T);
float volBlock = volume(P, L, T);
float cirBlock = circumference(P, L, T);
cout << "block which have P = " << P << " and L = " << L << " and T = "<< T << " have surface area = " <<
surfAreaBlock << " and volume = " << volBlock << " and cirBlock = " << cirBlock;
return 0;
}
也许你们中有人想重写并添加一些注释,哪些部分可以简化,这样我就可以更容易理解。
首先,您似乎应该将所有整数输入 double
而不是 int
,因为预计您的输入不一定是精确的整数(大概)。您还可以删除所有用于输入参数的重复函数。将其更改为单个函数并为每个变量调用该函数。
double getInput(const std::string& prompt)
{
double input(0.0);
do
{
std::cout << prompt << "\n-> " << std::flush;
// forces input to be a double type
while (!(std::cin >> input))
{
std::cout << "\n-> " << std::flush;
std::cin.clear();
std::cin.ignore(256, '\n'); ///< could use streamsize::max here
}
} while (input <= 0.0); ///< make sure it's positive
return input;
}