在句子中查找数组中所有出现的字符串列表，并将除第一个字母以外的所有内容替换为破折号

Question

我需要在一个句子中找到所有出现的字符串数组（原始 $list 有超过 780 个项目），并将除第一个字母以外的所有内容替换为 html 破折号。

这是我当前的代码：

function sanitize($string) {
    $list = array(
        "dumb",
        "stupid",
        "brainless"
    );

    # replace bad words
    $string = str_replace($list, '&ndash;', $string);
    return $string;
}

echo sanitize('hello, i think you are not intelligent, you are actually dumb and stupid.');

这是当前结果：

hello, i think you are not intelligent, you are actually – and –

结果应该是：

hello, i think you are not intelligent, you are actually d––– and s–––––

关于如何处理这个问题有什么想法吗？谢谢！

Answer 1

您可以使用 array_map 生成仅包含第一个字母的替换数组，并可选择为每个被替换的字符添加一个破折号：

function sanitize($string) {
    $list = array(
        "dumb",
        "stupid",
        "brainless"
    );

    $repl = array_map("dashReplace", $list);

    # replace bad words
    $string = str_replace($list, $repl, $string);
    return $string;
}

function dashReplace($str) {
    return $str{0}.str_repeat("-", strlen($str)-1);
}

echo sanitize('hello, i think you are not intelligent, you are actually dumb and stupid.');

您的示例的结果是：hello, i think you are not intelligent, you are actually d--- and s-----.

Answer 2

您可以使用这种基于正则表达式的方法 \G:

$str = 'hello, i think you are not intelligent, you are actually dumb and stupid.';
$list = array("dumb", "stupid", "brainless");

// use array_map to generate a regex of array for each word
$relist = array_map(function($s) { 
  return '/(?:\b(' . $s[0] . ')(?=' . substr($s, 1) . '\b)|(?!\A)\G)\pL/';
}, $list);

// call preg_replace using list of regex
echo preg_replace($relist, '-', $str) . "\n";

Code Demo

RegEx Demo

输出：

hello, i think you are not intelligent, you are actually d--- and s-----.

\G 断言位置在前一个匹配的末尾或第一个匹配的字符串的开头
(?!\A) 是负先行，以确保 \G 在行首不匹配

更新：

根据您在下面的评论，您可以使用这种不同的方法：

$str = 'word';
$relist = array_map(function($s) { return '/\b' . $s . '\b/'; }, $list);

echo preg_replace_callback($relist, function($m) { 
   return '<span class="bad">' . $m[0][0] . str_repeat('-', strlen($m[0])-1) . '</span>';
}, $str);

输出：

first <span class="bad">w---</span>

Answer 3

您可以使用 preg_replace_callback，但您需要为 $list 数组中的每一项添加反斜杠。

function sanitize($string) {
    $list = array(
        "/dumb/",
        "/stupid/",
        "/brainless/"
    );

    # replace bad words
    $string = preg_replace_callback($list,
        function ($matches) {
            return preg_replace('/\B./', '-', $matches[0]);
        }, 
        $string);
    return $string;
}

echo sanitize('hello, i think you are not intelligent, you are actually dumb and stupid.');

输出：

hello, i think you are not intelligent, you are actually d--- and s-----.

Code demo

在句子中查找数组中所有出现的字符串列表，并将除第一个字母以外的所有内容替换为破折号

Find all occurrences of list of strings in array inside a sentence, and replace everything except the first letter with dashes

php

regex

sanitization

str-replace