cypher distinct 使用 with 参数返回重复项

Question

MATCH (c:someNode)   WHERE  LOWER(c.erpId) contains (LOWER("1")) 
OR  LOWER(c.constructionYear) contains (LOWER("1")) 
OR  LOWER(c.label) contains (LOWER("1"))
OR  LOWER(c.name) contains (LOWER("1")) 
OR  LOWER(c.description) contains (LOWER("1"))with collect(distinct c) as rows, count(c) as total 
    MATCH (c:someNode)-[adtype:OFFICIAL_someNode_ADDRESS]->(ad:anotherObject) 

WHERE toString(ad.streetAddress) contains "1"     
OR toString(ad.postalCity) contains "1" 
with distinct rows+collect( c) as rows, count(c) +total as total
 UNWIND rows AS part

RETURN part order by part.name SKIP 20 Limit 20

当我运行下面的密码查询它returns重复的结果。此外，跳过似乎不起作用。我在做什么 wearng

Answer 1

当您使用 WITH DISTINCT a, b, c（或 RETURN DISTINCT a, b, c）时，这仅意味着您希望每个结果记录 ({a: ..., b: ..., c: ...}) 是不同的——它不会以任何方式影响a、b 或 c.

的任何列表的内容

下面是一个可能适合您的简化查询。它根本不使用 LOWER() 和 TOSTRING() 函数，因为它们看起来是多余的。它还仅使用单个 MATCH/WHERE 对来查找所有感兴趣的节点。 pattern comprehension 语法用作 WHERE 子句的一部分以获取 non-empty 列表 true 值当且仅当存在任何 anotherObject 节点（s ）出于兴趣。请注意，不需要 DISTINCT。

MATCH (c:someNode)
WHERE
  ANY(
    x IN [c.erpId, c.constructionYear, c.label, c.name, c.description]
    WHERE x CONTAINS "1") OR
  [(c)-[:OFFICIAL_someNode_ADDRESS]->(ad:anotherObject)
    WHERE ad.streetAddress CONTAINS "1" OR ad.postalCity CONTAINS "1"
    | true][0]
RETURN c AS part
ORDER BY part.name SKIP 20 LIMIT 20;

cypher distinct 使用 with 参数返回重复项

cypher distinct is returning duplicate using with parameter

neo4j

cypher

cypher-3.1