在 Activity 关闭时正确设置警报对话框?
Properly setting up an alertdialog on Activity closing?
我有一个 activity 有两个分数。我希望用户选择一个获胜者,如果他们在关闭时相同(即玩家 1 或玩家 2)。作为一个 .NET 用户,我主要尝试做 MessageBox。
不幸的是,根据我的阅读,android 不会以相同的方式执行 UI 线程。 activity 有 "a leaked window"。我查看了 SO,发现这个想法是将 "dismiss" 放在 "onPause" 中。但是,我没有看到 "onPause" 函数并且对如何实现它感到困惑。所以我尝试了下面的方法,但得到了同样的错误。
我可以对这个人做些什么来确保它正常工作?
public void onFinish(View v) {
//get scores
TextView score1tv = (TextView) findViewById(R.id.tvScore1);
score1 = score1tv.getText().toString();
TextView score2tv = (TextView) findViewById(R.id.tvScore2);
score2 = score2tv.getText().toString();
//Make sure they aren't the same
int i_Score1 = Integer.parseInt(score1);
int i_Score2 = Integer.parseInt(score2);
if (i_Score1 == i_Score2){
//alert user
new AlertDialog.Builder(this)
.setTitle("Duplicate score")
.setMessage("Whose score won the bout?")
.setPositiveButton(boutData[1], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
//fencer 1 won
score1 = "V" + score1;
dialog.dismiss();
}
})
.setNegativeButton(boutData[3], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
score2 = "V" + score2;
dialog.dismiss();
}
})
.setIcon(android.R.drawable.ic_dialog_alert)
.create()
.show();
}
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
编辑:这是我得到的解决方案,感谢我收到的帮助:
public void onFinish(View v) {
//get scores
TextView score1tv = (TextView) findViewById(R.id.tvScore1);
score1 = score1tv.getText().toString();
TextView score2tv = (TextView) findViewById(R.id.tvScore2);
score2 = score2tv.getText().toString();
//Make sure they aren't the same
int i_Score1 = Integer.parseInt(score1);
int i_Score2 = Integer.parseInt(score2);
if (score1 == score2){
//alert user
new AlertDialog.Builder(this)
.setTitle("Duplicate score")
.setMessage("Whose score won the bout?")
.setPositiveButton(boutData[1], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
//fencer 1 won
score1 = "V" + score1;
//close out
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
})
.setNegativeButton(boutData[3], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
score2 = "V" + score2;
//close out
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
})
.setIcon(android.R.drawable.ic_dialog_alert)
.create()
.show();
}
else{
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
}
将最后四行放入 else 子句中,并在您的 onClick 方法中做类似的事情。
此外,您不必手动调用 dialog.dismiss()。
我有一个 activity 有两个分数。我希望用户选择一个获胜者,如果他们在关闭时相同(即玩家 1 或玩家 2)。作为一个 .NET 用户,我主要尝试做 MessageBox。
不幸的是,根据我的阅读,android 不会以相同的方式执行 UI 线程。 activity 有 "a leaked window"。我查看了 SO,发现这个想法是将 "dismiss" 放在 "onPause" 中。但是,我没有看到 "onPause" 函数并且对如何实现它感到困惑。所以我尝试了下面的方法,但得到了同样的错误。
我可以对这个人做些什么来确保它正常工作?
public void onFinish(View v) {
//get scores
TextView score1tv = (TextView) findViewById(R.id.tvScore1);
score1 = score1tv.getText().toString();
TextView score2tv = (TextView) findViewById(R.id.tvScore2);
score2 = score2tv.getText().toString();
//Make sure they aren't the same
int i_Score1 = Integer.parseInt(score1);
int i_Score2 = Integer.parseInt(score2);
if (i_Score1 == i_Score2){
//alert user
new AlertDialog.Builder(this)
.setTitle("Duplicate score")
.setMessage("Whose score won the bout?")
.setPositiveButton(boutData[1], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
//fencer 1 won
score1 = "V" + score1;
dialog.dismiss();
}
})
.setNegativeButton(boutData[3], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
score2 = "V" + score2;
dialog.dismiss();
}
})
.setIcon(android.R.drawable.ic_dialog_alert)
.create()
.show();
}
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
编辑:这是我得到的解决方案,感谢我收到的帮助:
public void onFinish(View v) {
//get scores
TextView score1tv = (TextView) findViewById(R.id.tvScore1);
score1 = score1tv.getText().toString();
TextView score2tv = (TextView) findViewById(R.id.tvScore2);
score2 = score2tv.getText().toString();
//Make sure they aren't the same
int i_Score1 = Integer.parseInt(score1);
int i_Score2 = Integer.parseInt(score2);
if (score1 == score2){
//alert user
new AlertDialog.Builder(this)
.setTitle("Duplicate score")
.setMessage("Whose score won the bout?")
.setPositiveButton(boutData[1], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
//fencer 1 won
score1 = "V" + score1;
//close out
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
})
.setNegativeButton(boutData[3], new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
score2 = "V" + score2;
//close out
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
})
.setIcon(android.R.drawable.ic_dialog_alert)
.create()
.show();
}
else{
Intent intent = new Intent();
intent.putExtra("edittextvalue","value_here");
setResult(RESULT_OK, intent);
finish();
}
}
将最后四行放入 else 子句中,并在您的 onClick 方法中做类似的事情。
此外,您不必手动调用 dialog.dismiss()。